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babunello [35]
3 years ago
10

What type of reaction breaks the bonds that join the phosphate groups in an ATP molecule? What type of reaction breaks the bonds

that join the phosphate groups in an ATP molecule? anabolism hydrolysis entropic dehydration synthesis dehydration decomposition
Chemistry
1 answer:
Paraphin [41]3 years ago
4 0

Answer:

Hydrolysis

Explanation:

The phosphate groups in an ATP molecule are joined forming an ester group. Esters can be formed when an alcohol (-OH) bonds with an acid (-COOH, or, in the case of phosphoric acid, HPO_{5}). When this bonding occurs, the two molecules together lose a molecule of water, because the alcohol loses the hydroxyl and the acid loses an hydrogen, and the three atoms combine to form water. All the chemical bonds that are formed with the loss of a water molecule can also be broken using water, and this reaction is called hydrolysis.

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The combustion of acetylene gas is represented by this equation: 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
MAVERICK [17]

Answer:

Approximately 2.46\; \rm mol.

Explanation:

Make use of the molar mass data (M({\rm C_2H_2}) = 26.04\; \rm g \cdot mol^{-1}) to calculate the number of moles of molecules in that 64.0\; \rm g of \rm C_2H_2:

\begin{aligned}n({\rm C_2H_2}) &= \frac{m({\rm C_2H_2})}{M} \\ &= \frac{64.0\; \rm g}{26.04\; \rm g\cdot mol^{-1}}\approx 2.46\; \rm mol\end{aligned}.

Make sure that the equation for this reaction is balanced.

Coefficient of \rm C_2H_2 in this equation: 2.

Coefficient of \rm H_2O in this equation: 2.

In other words, for every two moles of \rm C_2H_2 that this reaction consumes, two moles of \rm H_2O would be produced.

Equivalently, for every mole of \rm C_2H_2 that this reaction consumes, one mole of \rm H_2O would be produced.

Hence the ratio: \displaystyle \frac{n({\rm H_2O})}{n({\rm C_2H_2})} = \frac{2}{2} = 1.

Apply this ratio to find the number of moles of \rm H_2O that this reaction would have produced:

\begin{aligned}n({\rm H_2O}) &= n({\rm C_2H_2}) \cdot \frac{n({\rm H_2O})}{n({\rm C_2H_2})} \\ &\approx 2.46\; \rm mol \times 1 = 2.46\; \rm mol\end{aligned}.

3 0
3 years ago
A 15.0 g piece of graphite is heated to 100.0°C and placed in a calorimeter. The
LenKa [72]

Answer:

0.714Jg^-10C^-1.

Explanation:

4 0
3 years ago
Read 2 more answers
The temperature of 6.24 L of a gas is increased from 25.0°C to 55.0°C at constant pressure. The new volume of the gas is Questio
Sphinxa [80]

Answer:

Heating this gas to 55 °C will raise its volume to 6.87 liters.

Assumption: this gas is ideal.

Explanation:

By Charles's Law, under constant pressure the volume V of an ideal gas is proportional to its absolute temperature T (the one in degrees Kelvins.)

Alternatively, consider the ideal gas law:

\displaystyle V = \frac{n \cdot R}{P}\cdot T.

  • n is the number of moles of particles in this gas. n should be constant as long as the container does not leak.
  • R is the ideal gas constant.
  • P is the pressure on the gas. The question states that the pressure on this gas is constant.

Therefore the volume of the gas is proportional to its absolute temperature.

Either way,

V\propto T.

\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1}.

For the gas in this question:

  • Initial volume: V_1 = \rm 6.24\; L.

Convert the two temperatures to degrees Kelvins:

  • Initial temperature: T_1 = \rm 25.0\;\textdegree{C} = (25.0 + {\rm 273.15})\; K = 298.15\;K.
  • Final temperature: T_1 = \rm 55.0\;\textdegree{C} = (55.0 + {\rm 273.15})\; K = 328.15\;K.

Apply Charles's Law:

\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1} = \rm 6.24\;L \times \frac{328.15\; K}{298.15\;K} = 6.87\;L.

7 0
3 years ago
Huge amount of energy is being produced in the core of a hot star due to
ss7ja [257]
The answer is below !


D.

5 0
3 years ago
Before you start an investigation, you see the Hazard symbol for Electrical Hazard. What safety steps should you follow when con
Fantom [35]

Explanation:

Safety hazards means they are are the unsafe working conditions which can cause the workmen injury, illness, or death. Safety hazards are some of the most common risks at the workplace.

Electrical hazards may be defined as a place or a condition which is dangerous and where a person working can come in contact with electrical contact with some energized equipment or any electrical conductor. There is always danger or a chance for the workmen to get injury or get a flash burn while working.

The safety steps are :

1. Follow the instruction properly

2. Take proper safety measures like wearing gloves, shoes, not touching any live wires, etc.

3. Follow the clean up procedure properly.

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