Question

A singly charged ion (q=−1.6×10−19) makes 7.0 rev in a 45 mT magnetic field in 1.29 ms. The mass of the ion in kg is

Answer 1

Answer:

$m=1.47\times 10^{-24}\ Kg$

Explanation:

Given that,

Charge, $q=1.6\times 10^{-19}\ C$

Revolution = 7 rev

magnetic field, B = 45 mT

Time, t = 1.29 ms

We need to find the mass of the ion. Let m be the mass. The formula for the mass in terms of time period is given by :

$m=\dfrac{qBT}{2\pi}\\\\m=\dfrac{1.6\times 10^{-19}\times 45\times 10^{-3}\times 1.29\times 10^{-3}}{2\pi}\\\\m=1.47\times 10^{-24}\ Kg$

So, the mass of the ion is equal to $1.47\times 10^{-24}\ Kg$.