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torisob [31]
3 years ago
13

A proton moves in a circular path perpendicular to a constant magnetic field. If the field strength of the magnet is increased,

does the diameter of the circular path increase, decrease, or remain the same?
Physics
1 answer:
zheka24 [161]3 years ago
5 0

Answer:

The diameter of the circular path decrease

Explanation:

The magnitude of the magnetic force exerted on the proton is given by:

 F=qvB

According to Newton's second law, this force is equal to the centripetal force. Therefore, we have:

F=F_c\\qvB=ma_c

Recall that a_c=\frac{v^2}{r}. Replacing and solving for B:

qvB=m\frac{v^2}{r}\\B=\frac{mv}{qr}

Thus, the field stregth is inversely proportional to the radius of the path and since the radius is directly proportional to the diameter, if the field strength increases, the diameter decreases.

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For the circuit in the previous part, what happens to the maximum current if the frequency is doubled and the inductance is halv
tamaranim1 [39]

Answer:

Following are the responses to these question:

Explanation:

Since the max^{m} is the current of ckt which depend on the reactance which   inductor that also enables the ckt and inductor resistance (X_L) for capacities

\to X_{C}=\frac{1}{W L}

for

\to X_{L}=wL

When w \longrightarrow 2w

L\longrightarrow \frac{L}{2}

then

\to X_{L}=2 w \times \frac{L}{2}=wL

 therefore, X_{L} remains at the same so, the maximum current remains the in same ckt.

4 0
3 years ago
Please need help with ? Number 20
zubka84 [21]

I would put B

Hope this helps!

7 0
3 years ago
Given w= 4+,- 0.02 A=2.0+,-0.2 and 3.0+,-0.6 what is the value of w\ A y square
In-s [12.5K]

Explanation:

w = (4.52 ± 0.02) cm, x = ( 2.0 ± 0.2) cm, y = (3.0 ± 0.6) cm. Find z = x + y - w and its uncertainty.

z = x + y - w = 2.0 + 3.0 - 4.5 = 0.5 cm

Dz = Dx + Dy + Dw = 0.2 + 0.6 + 0.02 = 0.82 rounding to 0.8 cm

So z = (0.5 ± 0.8) cm

Solution with standard deviations, Eq. 1b, Dz = 0.633 cm

z = (0.5 ± 0.6) cm

Notice that we round the uncertainty to one significant figure and round the answer to match.

8 0
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3 years ago
A charged particle moving in the magnetic field. For which angle magnetic force acting on charged particle is maximum.? ​
AnnyKZ [126]

Answer:

90o angle

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