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3 years ago

How long would it take 2.0x10^20 electrons to pass through a point in a conductor if the current was 10.0A?

1 answer:

6 0

1 coulomb of electric charge is carried by 6.25 x 10^18 electrons

1 Ampere = 1 coulomb per second
10 A = 10 coulombs per second

(2.0 x 10^20 electrons) x (coul / 6.25 x 10^18 electrons) / (10 coul/sec) =

(2.0 x 10^20) / (6.25 x 10^18 x 10) sec = 3.2 seconds

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A load of 250 kg is hung by a crane's cable. The load is pulled by a horizontal force such that the cable makes a 30 angle to th

Anna [14]

Answer:

1250 $\sqrt{3}$

Explanation:

Let's look at this in a simple manner, because it is.

The crane weights 250Kg. Okay.

Since it is hung, there is the acceleration of gravity being applied on it (10m/s²)

Since F = m * a

F = 250 * 10

F = 2500

Now we know that the downward Force is 2500N.

To find the force that is being applied on that 30° angle, we can multiply our 2500N by cos30°, which happens to be $\frac{\sqrt{3}}{2}$ .

Therefore, the force pulling the box in the cable's direction is:

$\frac{2500\sqrt{3} }{2} = 1250\sqrt{3}$

If you have any questions feel free to comment.

Have a great one and mark brainliest if it helped, please

8 0

2 years ago

What happens to the ratio of surface area to volume as the cell size increases without the cell changing shape?

docker41 [41]

The volume increases, but the surface area remains the same

6 0

4 years ago

Read 2 more answers

The 30-kg disk is originally spinning at v = 125 rad>s. If it is placed on the ground, for which the coefficient of kinetic f

irga5000 [103]

Answer:

t = 3.82 s

Ax = 147 N (←)

Ay = 294 N (+↑)

Explanation:

Given

m = 30.0 Kg

ωinitial = 125 rad/s

ωfinal = 0 rad/s

μC = 0.5

R = 0.3 m

t = ?

Ax = ?

Ay = ?

For the disk, we can apply

∑ τ = I*α

where I = m*R²/2

then

⇒ R*Ffriction = (m*R²/2)*α

⇒ R*(-μC*N) = R*(-μC*m*g) = (m*R²/2)*α

⇒ α = -2*μC*g / R

⇒ α = -2*(0.5)*(9.8) / 0.3 = -32.666 rad/s²

we can use the equation to get t:

α = Δω / t ⇒ t = Δω / α = (0 - 125) / (-32.666)

⇒ t = 3.82 s

The horizontal and vertical components of force which the member AB exerts on the pin at A during this time are

∑ Fx = 0 (+→)

Ax - Ffriction = 0

⇒ Ax = Ffriction = μC*m*g = (0.5)*(30)*(9.8) = 147 N

⇒ Ax = 147 N (←)

∑ Fy = 0 (+↑)

⇒ Ay - m*g = 0

⇒ Ay = m*g

⇒ Ay = 30*9.8 = 294 N

⇒ Ay = 294 N (+↑)

5 0

3 years ago

a super man I sitting on a tree 98m high with a he has rescued from a claws of a tiger. unfortunately the child shift and falls

nadezda [96]

Superman was a man who fell of the tree because he was up high at 98m and the. Tried to rescured Annie

5 0

2 years ago

Objects 1 and 2 attract each other with a gravitational force

Katena32 [7]

The new gravitational force of the two objects will be 432 N.

The given parameters:

Force between object 1 and object 2, F = 18 N

Let the mass of object 1 = m1
Let the mass of object 2 = m2
Let the distance between the two object = r

The gravitational force between the two objects is calculated by applying Newton's law of universal gravitation;

$F = \frac{Gm_1m_2}{r^2} \\\\G = \frac{Fr^2}{m_1m_2}\\\\G = \frac{Gm_1m_2}{r^2} \\\\G = \frac{18r^2}{m_1m_2}$

when the mass of the object 1 = 2m1
mass of the object 2 = 3m2
distance between the two object = ¹/₂r

$\frac{18r^2}{m_1 m_2 } = \frac{F_2(\frac{1}{2}r)^2 }{2m_1 \times 3m_2} \\\\\frac{18r^2}{m_1 m_2 } = \frac{F_2 \times r^2}{4 \times 2m_1 \times 3m_2} \\\\\frac{18r^2\times 4 \times 2m_1 \times 3m_2}{m_1 m_2\times r^2 } = F_2\\\\432 \ N = F_2$

Thus, the new gravitational force of the two objects will be 432 N.

Learn more about Newton's law of universal gravitation here: brainly.com/question/9373839

7 0

3 years ago