Question

8. Given the balanced chemical equation Br2 + 2 NaI -> 2 NaBr + I2 How many moles of sodium bromide (NaBr) could be produced from 0.172 mol of bromine (Br2)?

Answer 1

Since we are already given the balanced equation:

$Br_{2}+2NaI$ → $NaBr+I_{2}$

We can derive the molar ratios as: 1:2:1:1

That being said, we are given 0.172 moles of bromine ($Br_{2}$), so it has a ratio of 1:1 with sodium bromide ($NaBr$).

So we can take from that ratio, that when 0.172 moles of bromine are used, we are, in turn, going to get 0.172 moles of sodium bromide produced.