<span>Determine the root-mean-square sped of CO2 molecules that have an average Kinetic Energy of 4.21x10^-21 J per molecule. Write your answer to 3 sig figs.
</span><span>
E = 1/2 m v^2
If you substitute into this formula, you will get out the root-mean-square speed.
If energy is Joules, the mass should be in kg, and the speed will be in m/s.
1 mol of CO2 is 44.0 g, or 4.40 x 10^1 g or 4.40 x 10^-2 kg.
If you divide this by Avagadro's constant, you will get the average mass of a CO2 molecule.
4.40 x 10^-2 kg / 6.02 x 10^23 = 7.31 x 10^-26 kg
So, if E = 1/2 mv^2
</span>v^2 = 2E/m = 2 (4.21x10^-21 J)/7.31 x 10^-26 kg = 115184.68
Take the square root of that, and you get the answer 339 m/s.
The state in which all of the external forces acting upon an object are balanced; there is no acceleration. friction ..... quadrupling. doubling distance and quadrupling mass has the overall effect of the force
Answer:
D
Explanation:
I think but it is an better attempt than the other guy answer.
In order for you to calculate
for the mass of ammonium carbonate, you need to know the molar mass of it and
the nitrogen atoms in the compound. Ammonium carbonate has a molar mass of
96.08 grams per mole. There are two nitrogen atoms in ammonium carbonate which
is equal to 28.02 grams per mole. Divide the molar mass of nitrogen to the
ammonium carbonate, 28.02/96.08 x 100, we get 29.16wt% nitrogen.
