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kvasek [131]
3 years ago
8

What are ionic bonds???​

Chemistry
2 answers:
Debora [2.8K]3 years ago
5 0

Answer: ionic bonds

Explanation:

Ionic bonding is a type of chemical bonding that involves the electrostatic attraction between oppositely charged ions, or between two atoms with sharply different electronegativities, and is the primary interaction occurring in ionic compounds

LenaWriter [7]3 years ago
4 0

Answer:

<em><u>Ionic bonding is a type of chemical bonding that involves the electrostatic attraction between oppositely charged ions, or between two atoms with sharply different electronegativities, and is the primary interaction occurring in ionic compounds</u></em><em><u>.</u></em>

<em><u>W</u></em><em><u>i</u></em><em><u>t</u></em><em><u>h</u></em><em><u> </u></em><em><u>a</u></em><em><u>l</u></em><em><u>l</u></em><em><u> </u></em><em><u>m</u></em><em><u>y</u></em><em><u> </u></em><em><u>l</u></em><em><u>o</u></em><em><u>v</u></em><em><u>e</u></em><em><u>,</u></em>

<em><u>A</u></em><em><u>r</u></em><em><u>i</u></em><em><u>a</u></em><em><u>❤</u></em>

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Explanation:

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What is the vapor pressure of water at 105 degree Celsius?
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An acetic acid buffer solution is required to have a pH of 5.27. You have a solution that contains 0.010 mol of Acetic acid. Wha
dlinn [17]

Answer:

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Explanation:

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<em />

The pH of a buffer can be determined using Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

<em>Where pKa is pKa of the weak acid,  [A⁻] molar concentration of conjugate base and [HA] molar concentration of weak acid</em>

<em />

Replacing for the acetic buffer (pKa = 4.76):

pH = 4.76 + log [Sodium Acetate] / [Acetic Acid]

As you have 0.010 moles of acetic acid in 1L:

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5.27 = 4.76 + log [Sodium Acetate] / [0.010M]

0.51 = log [Sodium Acetate] / [0.010M]

10^0.51 = [Sodium Acetate] / [0.010M]

3.236 =  [Sodium Acetate] / [0.010M]

3.236 [0.010M] = [Sodium Acetate]

0.0324M = [Sodium Acetate]

<h3>Molarity of sodium acetate you will need to add is 0.0324M</h3>

<em />

7 0
3 years ago
A force of 2,500 pounds drags a truck 30 feet in 1/2 minute.
scoray [572]
The right subject for this question is physics.

To calculate the work you use the formula:

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To calculate the power you use the formula:

power = work / time

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3 0
3 years ago
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