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nikitadnepr [17]
3 years ago
13

Using this formula, to find K, what does E0 represent?. . K=10^(nE0/0.0592)

Chemistry
1 answer:
Nadusha1986 [10]3 years ago
5 0
E0,correctly written as EE^{o}, is the <span> standard electrode potential of the cell. This is usually used in the subject, electrochemistry. This is used to measure the difference in potential between two half cells used in an electrochemical cell. The o above signifies that it is at its standard state. </span>
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g What are the relative rates of diffusion of the three naturally occurring isotopes of krypton, 80Kr80Kr , 82Kr82Kr, and 83Kr83
emmasim [6.3K]

Solution :

According to the Graham's law of diffusion, we know that, the rate of the diffusion varies inversely to the molar mass of the gas, i.e.

Rate of diffusion, $r_d = \frac{a}{\sqrt M}$

where, the 'M' is the molar mass of the gas.

Now in the case of the isotopes of the Krypton,

Atomic mass of $^{80}Kr$ = 80 AMU

Atomic mass of $^{82}Kr$ = 82 AMU

Atomic mass of $^{83}Kr$ = 83 AMU

So the ratio of the rate of diffusion of the three isotopes are :

$M_{d,^{80}Kr}:M_{d,^{82}Kr}:M_{d,^{83}Kr}$

$=\frac{1}{\sqrt{80}}:\frac{1}{\sqrt{82}}:\frac{1}{\sqrt{83}}$

$=0.1118:0.1104:0.10976$

Dividing the above three with the smallest number among the three i.e. 0.10976, we get the relative rates of diffusion.

∴ $M_{d,^{80}Kr}:M_{d,^{82}Kr}:M_{d,^{83}Kr}$

 = 1.02 : 1.01 : 1

Hence the relative rate of diffusion are :

$^{80}Kr(1.02)>^{82}Kr(1.01)>^{83}Kr(1.00)$

3 0
3 years ago
ilver bromide is used to coat ordinary black-and-white photographic film, while high-speed film uses silver iodide. (a) When 56.
olya-2409 [2.1K]

Answer:

Mass of AgI formed=0.352g

Explanation:

AgNO3 + NaI ----‐>AgI + NaNO3

Volume of AgNO3 =5g/L

Mass of AgNO3 =C×V=0.25g

n(AgNO3)= m/Mr=0.0015mol

For NaI

V= 5g/l

Mass= C×v=0.25g

n=m/Mr=0.0017mol

n=0.0015mol

Mass=n× mr=0.352g

8 0
3 years ago
Can someone help me please?
morpeh [17]
This rock is balanced by roots on the ground that are very strong
8 0
3 years ago
A student wishes to prepare 2.00 Liters of a 0.100 M KIO3 (molecular weight 214). The proper procedure is to weigh out:_____
Vsevolod [243]

Answer:

B

Explanation:

A. Wrong

The volume of water in 2kg of water might not be 2L

D is correct.

Firstly, we need to know that the number of moles equals the mass over the molar mass. Doing this with the particular data in tie question would give 0.2M.

Hence it is essential that what we get is 0.2M in one liter. But since we are gunning for 2L, adding more than one liter of water would affect the molarity, that is why it now will be 0.1M in 2L

C is wrong

What is prepared here is 0.05M in 2L

B is wrong

What is needed is actually 2L of water and not the total volume of both being 2L

E is wrong

5 0
4 years ago
Read 2 more answers
What is the molar mass of magnesium tartrate
Leya [2.2K]

Answer:

172.385 g/mol

Explanation:

Magnesium Tartrate is C4H4MgO6

C - 12.01 g/mol

H - 1.01 g/mol

Mg - 24.305 g/mol

O - 16.00 g/mol

12.01(4) + 1.01(4) + 24.305 + 16(6) = 172.385 g/mol

3 0
3 years ago
Read 2 more answers
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