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Umnica [9.8K]
3 years ago
8

Change the following as indicated in the brackets. 8m (km,cm)​

Physics
2 answers:
allsm [11]3 years ago
7 0

Answer:

1000m=1km

so, 8m=8/1000 = 0.008km

1m=100cm

so, 8m=8×100=800

Jet001 [13]3 years ago
5 0

metres to kilometres = 1/1000

8 m ⇒ 0.008 km

metres to centimetres = × 100

8 m ⇒ 800 cm

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You are given aqueous solutions of six different substances and asked to determine whether they are strong, weak, or nonelectrol
kogti [31]

Answer:

Answer is explained below;

Explanation:

Electrolytes are any substances that dissociate into charged particles called ions when dissolved in water. The positively charged ions called cations and the negatively charged ions called anions move toward the negative and positive terminals (cathode and anode) of an electric circuit.

When a substance dissolved in water completely dissociates into ions, it is called a strong electrolyte. The aqueous solutions containing strong electrolytes conduct electricity very well and the examples include strong acids and soluble ionic compounds such as barium chloride, sodium hydroxide, etc.  

When a substance dissolved in water does not completely dissociate into ions, it is called a weak electrolyte. Since the aqueous solutions containing weak electrolytes have relatively few ions, their electrical conductivity is very low compared to the solutions containing strong electrolytes. Examples of weak electrolytes include weak acids and bases like acetic acid, ammonia, etc.

When a substance does not dissociate into ions when dissolved in water, it is called a nonelectrolyte. Since the aqueous solutions containing nonelectrolytes do not contain any ions, such solutions do not conduct electricity. Examples of nonelectrolytes are ethanol, aldehydes, glucose, ketones, etc.

If a solution contains dissolved ions, it conducts electricity and as the ion concentration increases, the conductivity also increases. To determine whether the aqueous solutions of six different substances are strong, weak, or nonelectrolytes, we can test them by applying a voltage to electrodes immersed in the solutions and a light bulb. By observing the brightness of the light bulb or by measuring the flow of electrical current, we can find out which solution contains a strong electrolyte or weak electrolyte, or nonelectrolyte.

If the solution contains a nonelectrolyte, the current flow is nil and the light bulb does not glow. If the solution contains a strong electrolyte, the current flow is very strong and so the brightness of the light bulb is very high. If the solution contains a weak electrolyte, the current flow is much low compared to the strong electrolyte and the light bulb glows, but the brightness is very low.

3 0
4 years ago
The blade of a lawn mower is rotating at an angular speed of 128 rad/s. The tangential speed of the outer edge of the blade is 3
stiv31 [10]

Answer:

0.25m

Explanation:

Using the expression that relates the angular velocity(w) and the linear velocity (v).

v= wr where;

w is the angular speed= 128rad/s

v is the linear speed = 32m/s

r is the radius

r = v/w

r = 32/128

r = 0.25m

The radius of the blade is 0.25m

4 0
3 years ago
What is the Outer Space Treaty? What idea that Wood discusses does... What is the Outer Space Treaty? What idea that Wood discus
Veronika [31]

Answer:

The Outer Space Treaty, formally the Treaty on Principles Governing the Activities of States in the Exploration and Use of Outer Space, including the Moon and Other Celestial Bodies, is a multilateral treaty that forms the basis of international space law.

Explanation:

6 0
3 years ago
Which should not be a part of scientific inquiry?
lisabon 2012 [21]

I would say;

a - bias.

8 0
4 years ago
A rectangular trough, 2.0 m long, 0.70 m wide, and 0.40 m deep, is completely full of water. One end of the trough has a small d
Stella [2.4K]

Answer:

speed does water emerge from the hole v= 2.8 m/sec

Explanation:

the depth of the  rectangular trough h = 0.40 m   full of water

Also, given One end of the trough has a small drain plug right at the bottom edge.

we have to find the speed does water emerge from the hole.

This can be done using law of conservation of energy

the potential energy of water will be converted into kinetic energy as

\frac{1}{2}mv^2= mgh

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h= depth, g= acceleration due to gravity and v= velocity of water from the hole

plugging the values

v= \sqrt{2\times9.81\times0.40}

v= 2.8 m/sec

8 0
4 years ago
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