Answer:Racquet force is twice of Player force
Explanation:
Given
ball arrives at a speed of 
ball returned with speed of 
average Force imparted by racquet on the ball is given by

where 
time of contact of ball with racquet


When it land on the player hand its final velocity becomes zero and time of contact is same as of racquet


From 1 and 2 we get

Hence the magnitude of Force by racquet is twice the Force by player
the normal force is the force applied opposite to the weight
of the was box. So the normal force is equal to the weight of the box = 24 kg
*(9.81 m/s2) = 235.44 N
the acceleration of the box be solve using newtons 2nd
law of motion:
F = ma
a = F/ m = 585 N/ 24 kg = 24.38 m/s2
Answer:
acceleration of person = 9.77 m/s²
Explanation:
given data
latitude = 40 degree
to find out
Calculate the acceleration of a person
solution
we know that here 40 degree = 0.698 rad
so
acceleration of person = g - ω²R ...............1
and 1 rotation complete in 24 hours = 360 degree
here g is 9.81
so we know Earth angular speed ω = 7.27 ×
rad/s and R is earth radius that is 6.37 ×
m
so
put here value in equation 1 we get
acceleration of person = g - ω²R
acceleration of person = 9.81 - (7.27 ×
)² × 6.37 ×
acceleration of person = 9.77 m/s²
1 in=2.54 cm=(2.54 cm)(1 m/100 cm)=0.0254 m
Therefore:
1 in=0.0254 m
1 in³=(0.0254 m)³=1.6387064 x 10⁻⁵ m³
Therefore:
8.06 in³=(8.06 in³)(1.6387064 x 10⁻⁵ m³ / 1 in³)≈1.321 x 10⁻⁴ m³.
Answer: 8.06 in³=1.321 x 10⁻⁴ m³
Answer:
Waves transfer energy, not motion