B) 20-40 percent
I hope this helps
Answer:The central spot becomes Dark
Explanation: it become dark because as the wavelength reduces,the velocity in the detector decreases, this time by 90degrees
Answer:
P = 140000 [Pa]
Explanation:
To solve this problem we must remember that pressure is defined as the relationship between Force on the area of a body.
In this particular problem, we are given the force acting on the upper surface of the block, including the force exerted by the atmospheric pressure.
P = F/A
where:
P = pressure [Pa] (units of Pascals)
F = force = 3.5*10⁴ [N]
A = area = 0.25 [m²]
P = 3.5*10⁴/0.25
P = 140000 [Pa]
Answer:
aaa
Explanation:
= Mass of the Earth = 5.98 × 10²⁴ kg
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
= Distance from the center of the Moon to the center of Earth = 6371000 m
= Distance from the center of the earth center to sun center
= Mass of moon = ![7.35\times 10^{22}\ kg](https://tex.z-dn.net/?f=7.35%5Ctimes%2010%5E%7B22%7D%5C%20kg)
M = Mass of sun = ![1.989\times 10^{30}\ kg](https://tex.z-dn.net/?f=1.989%5Ctimes%2010%5E%7B30%7D%5C%20kg)
![F_1=G\frac{m_em_m}{r_1^2}\\\Rightarrow F_1=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 7.35\times 10^{22}}{(384000000)^2}\\\Rightarrow F_1=1.988\times 10^{20}\ N](https://tex.z-dn.net/?f=F_1%3DG%5Cfrac%7Bm_em_m%7D%7Br_1%5E2%7D%5C%5C%5CRightarrow%20F_1%3D6.67%5Ctimes%2010%5E%7B-11%7D%5Cfrac%7B5.98%5Ctimes%2010%5E%7B24%7D%5Ctimes%207.35%5Ctimes%2010%5E%7B22%7D%7D%7B%28384000000%29%5E2%7D%5C%5C%5CRightarrow%20F_1%3D1.988%5Ctimes%2010%5E%7B20%7D%5C%20N)
![F_2=G\frac{Mm_e}{r_1^2}\\\Rightarrow F_2=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 1.989\times 10^{30}}{(149.6\times 10^9+6371000+695.51\times 10^6)^2}\\\Rightarrow F_2=3.511\times 10^{22} N](https://tex.z-dn.net/?f=F_2%3DG%5Cfrac%7BMm_e%7D%7Br_1%5E2%7D%5C%5C%5CRightarrow%20F_2%3D6.67%5Ctimes%2010%5E%7B-11%7D%5Cfrac%7B5.98%5Ctimes%2010%5E%7B24%7D%5Ctimes%201.989%5Ctimes%2010%5E%7B30%7D%7D%7B%28149.6%5Ctimes%2010%5E9%2B6371000%2B695.51%5Ctimes%2010%5E6%29%5E2%7D%5C%5C%5CRightarrow%20F_2%3D3.511%5Ctimes%2010%5E%7B22%7D%20N)
![\frac{F_1}{F_2}=\frac{1.988\times 10^{20}}{3.511\times 10^{22}}\\\Rightarrow \frac{F_1}{F_2}=0.00566\\\Rightarrow F_1=F_20.00566](https://tex.z-dn.net/?f=%5Cfrac%7BF_1%7D%7BF_2%7D%3D%5Cfrac%7B1.988%5Ctimes%2010%5E%7B20%7D%7D%7B3.511%5Ctimes%2010%5E%7B22%7D%7D%5C%5C%5CRightarrow%20%5Cfrac%7BF_1%7D%7BF_2%7D%3D0.00566%5C%5C%5CRightarrow%20F_1%3DF_20.00566)
Hence the force of moon on earth is 0.00566 times the force of earth on moon center to center
Answer: The two answers are in explanation.
Explanation: Please find the attached files for the solution