Answer:
the approximate pressure in the flask after 400. s = 1.2atm
Explanation:
The detailed explanation is shown below
Moles of Na_2O
- Given mass/Molar mass
- 35/62
- 0.56mol
2 mols Na_2O produces 1 mol sodium carbonate.
1 mol sodium oxide produces 0.5mol sodium carbonate
Moles of sodium carbonate
Molar mass
- 2(23)+12+3(16)
- 46+12+48
- 106g/mol
Mass
There are three carbon and 8 hydrogen present in propane molecule. The Lewis structure of propane is shown as:
Three molecules of such carbon atoms bound to eight molecules with hydrogen atoms make up the organic complex propane molecule.
It is known that carbon has 4 valence electrons and hydrogen has one valence electron. Carbon needs 4 extra electrons to complete its octet hence, it will share its electrons with with 4 hydrogen atom and complete its octet.
Carbon will be formed 4 bond . Three bond with hydrogen and one bond with carbon atom.
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Answer:
4.79 g of water
Explanation:
From the reaction equation;
C2H6(g) + 7/2O2(g) ----> 2CO2(g) + 3H2O(g)
Next we convert the given masses of reactants to moles of reactants.
For ethane; number of moles = mass/molar mass= 7.82g/ 30gmol-1= 0.261 moles
For oxygen; number of moles= 9.9 g/32gmol-1= 0.31 moles
Next we determine the limiting reactant, the limiting reactant yields the least amount of product.
For ethane;
From the reaction equation,
1 mole of ethane yields 3 moles of water
0.261 moles of Ethan yields 0.261 ×3 = 0.783 moles of water
For oxygen;
3.5 moles of oxygen yields 3 moles of water
0.31 moles of oxygen yields 0.31 × 3/3.5 = 0.266 moles of water
Hence oxygen is the limiting reactant.
Mass of water produced = 0.266 moles of water × 18gmol-1 = 4.79 g of water