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kolezko [41]
3 years ago
14

A metal stand specifies a maximum load of 450 lb. Will it support an aquarium that weighs 59.5 lb and is filled with 37.9 L of s

eawater (d = 1.03 g/mL)?
Chemistry
1 answer:
DedPeter [7]3 years ago
5 0

First solve the mass of 37.9 L seawater

M = 37.9 L ( 1000 ml / 1L ) ( 1.03 g / ml)

M = 39037 g

Then convert it to lb

M = 39037 g ( 1 lb / 453.592 g)

M = 86.06 lb

<span>Total weight = 86.06 lb + 59.5 lb = 145.56 lb so it can support the aquarium</span>

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While out on a hike, you find an unknown mineral. How would you test the mineral to find out what it is?
Mashcka [7]
Probably look up the descriptions of the element and see if it matches the mineral.
5 0
3 years ago
What is the mass of 0.80 moles of Mg? (1 point)
Aneli [31]

Answer:

m = 19 grams

Explanation:

Given that,

No. of moles, n = 0.8

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We need to find the mass of 0.80 moles of Mg. We know that given mass to the molar mass is equal to no of moles. Let the mass is m. So,

n=\dfrac{m}{M}\\\\m=n\times M\\\\m=0.8\times 24.305 \\\\m=19.444\ \text{grams}

or

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6 0
3 years ago
250 ml of seawater and we inked each molecule with pink color, then we mixed this 250 ml in the ocean. After mixing you took 250
Marysya12 [62]

Answer:

9.77 × 10⁹ molecules

Explanation:

Since the density of water is 1 g/cm³ = 1000 g/L

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We know density = mass/volume

mass = density × volume = 1000 g/L × 0.250 L = 250 g

Now we calculate the number of moles of sea water in 250 g, 250 mL of sea water.

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We now calculate the number of molecules present in the 250 mL of sea water.

n = N/N' where N = number of molecules, N' = avogadro's number = 6.022 × 10²³/mol

So,N =nN' = 13.89 mol × 6.022 × 10²³/mol = 8.36 × 10²⁴ molecules

Now, the volume of the ocean is 1.337 × 10¹⁸ m³ = 1.337 × 10¹⁵ L

Since the 250 mL sea water is mixed with the ocean, the number of molecules per liter is 8.36 × 10²⁴ molecules/1.337 × 10¹⁵ L = 6.25 × 10⁹ molecules/L

If we now take 250 mL out of the ocean, the number of molecules in this 250 mL will be 6.25 × 10⁹ molecules/L × 250 mL =  6.25 × 10⁹ molecules/L × 0.250 L = 9.77 × 10⁹ molecules.

So, we have 9.77 × 10⁹ molecules of pink molecules in the 250 mL after mixing in the ocean.

6 0
3 years ago
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user100 [1]
Iodine has an electronegativity of 2.5, and potassium has an electronegativity of 0.8, so the difference is:
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7 0
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