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Arturiano [62]
3 years ago
7

In a constant pressure calorimeter, the temperature of 60.0 g of water increases by 4.50c. What amount of heat is transferred to

the water?
Chemistry
1 answer:
timama [110]3 years ago
7 0

Answer:

it's been 4 hours so I assume you found your answer to I'ma just boggie on in here and take these points

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Under what conditions does the molar volume of a gas decrease
nydimaria [60]

Answer:

Gases are compressible, meaning that when put under high pressure, the particles are forced closer to one another. This decreases the amount of empty space and reduces the volume of the gas. Gas volume is also affected by temperature. When a gas is heated, its molecules move faster and the gas expands.

4 0
3 years ago
Read 2 more answers
How many fluorine atoms bond with calcium to form calcium fluoride? one two three four five
Elena-2011 [213]
Calcium fluoride.
Ca is metal, F is non-metal, so they form ionic bond.
Ca as metal can form only positive ion. Ca in the second group, so the charge of Ca ion is 2+.   Ca²⁺
F is in the 17th group, so it has 7 electrons on the last level. It is non-metal, non-metal, so it has negative charge -(8-7)=-1. "8" because on the last level cannot be more than 8 electrons. F-ion is F¹⁻.

Ca²⁺  F¹⁻
Number of positive charges should be equal to number of negative charges,
Formula of calcium fluoride
CaF2.
2 atoms Fluorine bond with Calcium.
7 0
3 years ago
What is the molarity of 20.2 g of potassium nitrate, KNO3, in enough water to make 250.0 mL of solution
KATRIN_1 [288]

Answer:

0.8M

Explanation:

CM=n/V

8 0
3 years ago
Whose main job is to help a plant cell make proteins
hoa [83]

Answer:

Water

Explanation:

Because water is very important

7 0
2 years ago
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Calculate the pH of the solutions: [H^+]= 1.6 x 10^-3 M
Yuliya22 [10]

Answer:

A) pH = 2.8

B) pH = 5.5

C) pH = 8.9

D) pH = 13.72

Explanation:

a) [H⁺]  = 1.6 × 10⁻³ M

pH = -log [H⁺]

pH = -log [1.6 × 10⁻³ ]

pH = 2.8

b) [H⁺]  = 3 × 10⁻⁶

pH = -log [H⁺]

pH = -log [3 × 10⁻⁶ ]

pH = 5.5

c) [OH⁻] = 8.2 × 10⁻⁶

pOH = -log[OH]

pOH = -log[8.2 × 10⁻⁶]

pOH = 5.1

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 5.1

pH = 8.9

d) [OH⁻] = 0.53 M

pOH = -log[OH]

pOH = -log[0.53]

pOH = 0.28

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 0.28

pH = 13.72

5 0
3 years ago
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