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Harman [31]
3 years ago
8

A spring has a spring constant of 81 N · m−1. What is the force (in N) required to do the following? (Enter the magnitude.) (a)

compress the spring by 6 cm N (b) expand the spring by 17 cm N
Physics
1 answer:
DochEvi [55]3 years ago
8 0

Explanation:

It is given that,

Spring constant, k = 81 N/m

We need to find the force required to :

(a) Compress the spring by 6 cm i.e. x₁ = 6 cm = -0.06 m

It can be calculated using Hooke's law as :

F = - k(-x₁)

F=81\ N/m\times 0.06\ m

F = 4.86 N

(b) Expand the spring by 17 cm i.e. x₂ = 17 cm = +0.17 m

So, F = -kx₂

F=-81\ N/m\times 0.17\ m

F = -13.77 N

Hence, this is the required solution.

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Given that the effective mass ratio of the electron is 0.11 and the effective mass ratio of the hole is 0.35, please calculate t
fomenos

Complete question:

CdTe has a band-gap energy εg of 1.6 eV and a dielectric constant εr of 10.9.

Given that the effective mass ratio of the electron is 0.11 and the effective mass ratio of the hole is 0.35, please calculate the ground-state energy (ie: n=1) of the donor and acceptor bands along with their orbital radii.

Answer:

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Explanation:

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The ground-state energy for donor = 13.606 eV x M*/(M₀εr²)

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                                                           = 13.606 eV x 0.11/((10.9)²)

                                                           = 2.6 meV

The ground-state energy for acceptor  = 13.606 eV x M*/(M₀εr²)

                                                                 =  13.606 eV x Mh/(εr²)

                                                                 = 13.606 eV x 0.35/((10.9)²)

                                                                 = 40.1  meV

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