Answer:
E = 1580594.95 N/C
Explanation:
To find the electric field inside the the non-conducting shell for r=11.2cm you use the Gauss' law:
(1)
dS: differential of the Gaussian surface
Qin: charge inside the Gaussian surface
εo: dielectric permittivity of vacuum = 8.85 × 10-12 C2/N ∙ m2
The electric field is parallel to the dS vector. In this case you have the surface of a sphere, thus you have:
(2)
Qin is calculate by using the charge density:
(3)
Vin is the volume of the spherical shell enclosed by the surface. a is the inner radius.
The charge density is given by:

Next, you use the results of (3), (2) and (1):

Finally, you replace the values of all parameters, and for r = 11.2cm = 0.112m you obtain:

hence, the electric field is 1580594.95 N/C
Answer:
This causes the amplitude of the oscillation to decay over time. The damped oscillation frequency does not equal the natural frequency. Damping causes the frequency of the damped oscillation to be slightly less than the natural frequency
A. anything less than 3.0 magnitude on a richters scale usually can't be felt by humans but instruments can pick it up.
-60 degrees north north north
Answer:
2 hrs 45 minutes
Explanation:
You have to minus one hr because of tome change