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HACTEHA [7]
3 years ago
7

Solve the problems here on the pic

Physics
2 answers:
Korvikt [17]3 years ago
4 0

Answer:30,3.33,300

Explanation:divide 15 by the decimal

Gekata [30.6K]3 years ago
4 0
30 is the answer to the problem
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How long is the image of a metrestick formed by a plane mirror?
Zinaida [17]

A plane mirror doesn't change the apparent size or shape of things.

-- If the meter stick is held parallel to the mirror, or is lying on the mirror,
then its image in the mirror is 1 meter long.

-- If the meter stick is held perpendicular to the mirror, or is standing on
the mirror, or pointing directly at it, then its image in the mirror has no length.

7 0
3 years ago
You drop a rock off of a cliff at exactly the edge after 25 seconds exactly you hear a splash your physics friend tells you the
Reptile [31]
The speed of sound is 340.29 meters per second.

Knowing that, we can calculate how high this cliff is by 340.29 * .4 

The cliff is 340.29 * .4 = 136.12 meters
8 0
4 years ago
The apparent height of a building 10.5 km away is 0.02 radians. What is the approximate height of the building to the nearest me
Ksenya-84 [330]

Answer:

Approximate height of the building is 23213 meters.

Explanation:

Let the height of the building be represented by h.

0.02 radians = 0.02 × \frac{180^{o} }{\pi }

                     = 0.02 x (180/\frac{22}{7})

0.02 radians  = 1.146°

10.5 km = 10500 m

Applying the trigonometric function, we have;

Tan θ = \frac{opposite}{adjacent}

So that,

Tan 1.146° = \frac{h}{10500}

⇒ h = Tan 1.146° x 10500

      = 2.21074 x 10500

      = 23212.77

h = 23213 m

The approximate height of the building is 23213 m.

8 0
3 years ago
The speed of sound through argon is shown.
kobusy [5.1K]

Answer:

3200

Explanation:

5 0
3 years ago
Read 2 more answers
2. Superman is able to fly at an average velocity of 355 m/s. If he begins at a position of
lesya [120]

Answer:

final position = 325 m

Explanation:

distance covered in 1 second = speed x time

                                                 = 355 m/s  x   1 s

                                                 = 355 m

∴  final position =  initial position + distance covered

                          =  - 30 m  +  355 m

                          =  325 m

4 0
3 years ago
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