The force of the table upon the cup is 2.9106 N
Let's use the given equation, F = ma, to find out the force of each of the objects given.
A) F = 5 x 10 = 50 N
B) F = 5 x 20 = 100 N
C) F = 20 x 4 = 80 N
D) F = 20 x 3 = 60 N
The object with the greatest force is object B, with a force of 100 N.
Hope this helps! :)
Answer:
at x=0
=W*L/L
and
=W-
Explanation:
Solve for the tension in the left rope, TL, in the special case that x=0. Be sure the result checks with your intuition. Express your answer in terms of W and the dimensions L and x. Not all of these variables may show up in the solution.
moments is the product of force and the perpendicular distance in line of the action of the given force
from the principle of moments which states that the sum of clockwise moments ,must be equal to the sum of anticlockwise moments.
also, sum of upward forces must be equal to sum of downward forces
Going by the aforementioned,
taking moments about 
W*(l-x)=
*(L)
=W*(L-x)/(L)..............1
at x=0
=W*L/L
also
+
=W
=W-
Answer:

Explanation:
Assuming that cars 4 and 5 have same mass so that the momentum
P=mv where m is mass and v is velocity hence
Momentum=0+2mv+3mv=5mv
The final mass is 2m+3m=5m
From aw of conservation of momentum
hence 
Therefore, the speed is 