Two long wires hang vertically. Wire 1 carries an upward current of 1.50 A . Wire 2,20.0cm to the right of wire 1, carries a dow
nward current of 4.00 A . A third wire, wire 3 , is to be hung vertically and located such that when it carries a certain current, each wire experiences no net force. (c) the magnitude and direction of the current in wire 3 .
The magnitude of the current in wire 3 is 2.4 A and in a direction pointing in the downward direction.
The force per unit length between two parallel thin current-carrying and wires at distance ' r ' is given by ....(1) .
If the current is flowing in both wires in the same direction, and the force between them will be the attractive force and if the current is flowing in opposite direction in wires then the force between them will be the repulsive force.
A schematic of the information provided in the question can be seen in the image attached below.
From the image, force on wire 2 due to wire 1 = force on wire 2 due to wire 3
Using equation (1) , we get
I₃ = 2.4 A and the current is pointing in the downward direction
Learn more about the magnitude and direction of forces here:
Night vision is the ability to see in low-light conditions. Whether by biological or technological means, night vision is made possible by a combination of two approaches: sufficient spectral range, and sufficient intensity range.
Turn it into a triangle pretty much. total displacement eastward is 15cm. total displacement northward is 35cm. now use the Pythagorean theorem which will be squareroot of 15squared+35squared. this gives you 38.08cm northeastward.<span />
and
wires at distance ' r ' is given by
....(1) .
