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Nimfa-mama [501]
3 years ago
13

An airplane has wings, each with area A, designed so that air flows over the top of the wing at 265 m/s and underneath the wing

at 234 m/s. If the mass of the airplane is 7.2×10^3 kg then what is the area of each wing needed to produce enough lift? (air = 1.29 kg/m^3 )
Physics
1 answer:
exis [7]3 years ago
7 0

Answer

given,

Pressure on the top wing = 265 m/s

speed of underneath wings = 234 m/s

mass of the airplane =  7.2 × 10³ kg

density of air =  1.29 kg/m³

using Bernoulli's equation

 P_1 + \dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho v_2^2

 \Delta P =\dfrac{1}{2}\rho (v_2^2-v_1^2)

 \Delta P =\dfrac{1}{2}\times 1.29\times (265^2-234^2)

 \Delta P =9977.5 Pa

Applying newtons second law

2 Δ P x A - mg = 0

A =\dfrac{mg}{2\Delta P}

A =\dfrac{7.2\times 10^3 \times 9.8}{2\times 9977.5}

    A = 3.53 m²

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