Ask question

Ask question

All categories

3 years ago

14

Racheal brought chocolate and vanilla to school for her birthday.80 students decided to take a cupcake and 56 of them took vanil

la.what percentage of students picked vanilla.

1 answer:

anyanavicka [17]3 years ago

3 0

Answer:

70%

Step-by-step explanation:

56 vanilla cupcakes

------------------------------- = 0.7, or 0.7(100%), or 70%

80 students

70% of students picked vanilla.

You might be interested in

The question is on the picture

Ghella [55]

Answer:6/10

Step-by-step explanation:

hope youdo well

7 0

3 years ago

Warren just found his old journal in a drawer and has decided to start making 1 journal entry every day. There were already 8 en

xenn [34]

Since x is the days And y is the entries And there are 8entries already the equation should be y=x+8

5 0

2 years ago

I need a 10 squared root chart

bonufazy [111]

here you gooo
you can just copy this
this is the exact squared root chart

5 0

3 years ago

A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha

White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

$\frac{dB}{dt} = rB-k$

$\Rightarrow \frac{dB}{dt} - rB=-k$ .......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor $=e^{\int p(t) dt$

$=e^{\int (-r)dt$

$=e^{-rt}$

Multiplying the integrating factor the both sides of equation (1)

$e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}$

$\Rightarrow e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt$

Integrating both sides

$\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt$

$\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C$ [ where C arbitrary constant]

$\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}$

Initial condition B=7864 when t =0

$\therefore 7864= \frac{k}{r} - Ce^0$

$\Rightarrow C= \frac{k}{r} -7864$

Then the general solution is

$B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}$

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

$B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}$

$\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0$

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

=$1573.17

4 0

3 years ago

HELPP, solve for x and y

Triss [41]

Answer:

x=23, y=157

Step-by-step explanation:

23 and x are on equalivent sides of the rhombus so they are equal. To solve for y you have to multiple 23 by 2. Getting 46 you subtract that from 360 to get 314. Dividing 314/2 you get 157.

5 0

2 years ago

Read 2 more answers