Passband to baseband conversion: Consider the following passband signal,

Question 1 : Replacement [42 Pts] Consider the following page reference string:

MakcuM [25]

Answer:

Optimal

Time 123456789101112

RS. ecbeagdcegda

F0. eeeeeeeee e e a

F1 c c c c c c c c c c c

F2 b b b g g g g g g g

F3 a a d d d d d d

Page fault? * * * * * * *

Total page fault:7

2. LRU

Time 1 2 3 4 5 6 7 8 9 10 11 12

RS e c b e a g d c e g d a

F0 e e e e e e e c c c c a

F1 c c c c g g g g g g g

F2 b b b b d d d d d d

F3 a a a a e e e e

Page fault? Y Y Y N Y Y Y Y Y N N Y Total page fault:9

3. LRU approximation algorithm: Second chance

Time 1 2 3 4 5 6 7 8 9 10 11 12

RS e c b e a g d c e g d a

F0 0,e 0,e 0,e 1,e 1,e 0,e 0,e 0,e 1,e 1,e 1,e 0,e

F1 0,c 0,c 0,c 0,c 0,g 0,g 0,g 0,g 1,g 1,g 0,g

F20,b0,b0,b0,b0,d0,d0,d0,d1,d0,dF30,a0,a0,a0,c0,c0,c0,c0,a

Page fault? YYYNYYYYNNNY

Total page fault: 8

4 0

3 years ago

Read 2 more answers

Help please? this math is way too difficult

hoa [83]

Answer:

makin this,ill help with your math

Explanation:

6 0

3 years ago

A point in the x-y plane is represented by its x-coordinate and y-coordinate. Design the class Point that can store and process

Black_prince [1.1K]

Answer:

#include <iostream>

#include <iomanip>

using namespace std;

class pointType

{

public:

pointType()

{

x=0;

y=0;

}

pointType::pointType(double x,double y)

{

this->x = x;

this->y = y;

}

void pointType::setPoint(double x,double y)

{

this->x=x;

this->y=y;

}

void pointType::print()

{

cout<<"("<<x<<","<<y<<")\n";

}

double pointType::getX()

{return x;

}

double pointType::getY()

{return y;

}

private:

double x,y;

};

int main()

{

pointType p2;

double x,y;

cout<<"Enter an x Coordinate for point ";

cin>>x;

cout<<"Enter an y Coordinate for point ";

cin>>y;

p2.setPoint(x,y);

p2.print();

system("pause");

return 0;

}

5 0

3 years ago

Container need to be inspected

Sedaia [141]

Answer:

than look inside it

Explanation:

well if you need to inspect something, looking is very important

7 0

3 years ago

Calculate the amount of power (in Watts) required to move an object weighing 762 N from point A to point B within 29 seconds. Di

Tresset [83]

Answer:

0.556 Watts

Explanation:

w = Weight of object = 762 N

s = Distance = 5 m

t = Time taken = 29 seconds

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

Equation of motion

$s=ut+\frac{1}{2}at^2\\\Rightarrow a=\frac{2\times (s-ut)}{t^2}\\\Rightarrow a=\frac{2\times (5-0)}{29^2}=\frac{10}{481}$

Mass of the body

$m=\frac{w}{g}=\frac{762}{9.81}$

Force required to move the body

$F=ma\\\Righarrow F=\frac{762}{9.81}\times \frac{10}{481}$

Velocity of object

$v=u+at\\\Rightarrow v=0+\frac{10}{481}\times 29\\\Rightarrow v=\frac{10}{29}$

Power

$P=Fv\\\Rightarrow P=\frac{762}{9.81}\times \frac{10}{481}\times \frac{10}{29}=0.556\ W$

∴ Amount of power required to move the object is 0.556 Watts

7 0

4 years ago