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Lady bird [3.3K]

3 years ago

6

What material property would still cause strain in a strain gauge that is positionedperpendicular to the direction of force if i

t were fully bonded in a high strain region of thespecimen? If this occurs, then the set up must be calculated as a two-active gauge set up.Will this set up continue to compensate for the environmental factor?

1 answer:

svetlana [45]3 years ago

5 0

Answer:

oof

Explanation:

I don't know but please don't report me

I am trying to do a challenge

Thank you-

If you don't report me!

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A relatively nonvolatile hydrocarbon oil contains 4.0 mol % propane and is being stripped by direct superheated steam in a strip

hram777 [196]

Answer:

Number of Trays = Six (6)

Explanation:

Given that: y' = 25x' , in terms of molecular ratio, we can write it as

$\frac{Y'}{1 + Y'} =25 \frac{X'}{1 + X'}$ ......... 1

after plotting this we get equilibrium curve as shown in the attached picture.

inlet concentration and outlet concentration of liquid phase is

x₂ = 4% = 0.04 (inlet)

so that can be converted into molar

$X_2 = \frac{x_2}{1-x_2} = \frac{0.04}{1-0.04} = 0.04167$

and

x₁ = 0.2% = 0.002

$X_1 = \frac{x_1}{1-x_1} = \frac{0.002}{1-0.002} = 2.004*10^{-3}$

Now we have to use the balance equation a

$\frac{G_s}{L_s} = \frac{X_2-X_1}{Y_2-Y_1}$ .............. a

here amount of solute is comparably lower than

Here we have

L = 300 kmol (total)

$L_s$ = 300(1 - 0.04) = 288 kmol pure oil

G = $G_s$ = 11.42 kmol

$Y_1$ = 0 , solvent free steam

substitute into the equation a

$\frac{11.42}{288} = \frac{0.04167 - 2*10^{-3}}{Y_2 - 0}$

Y₂ = 1.0003

Now plot the point A(X₁ , Y₁) and B(X₂ , Y₂) and join them to construct operating line AB.

Starting from point B, stretch horizontal line up to equilibrium curve and from there again go down to operating line as shown in the picture attached. This procedure give one count of tray and continue the same procedure up to end of operating.

at last count, the number of stage, gives 6.

∴ <em>Number of trays = 6</em>

5 0

4 years ago

Read 2 more answers

How to update android 4.4.2 to 5.1 if there isnt any update available

gulaghasi [49]

Answer:

You cant update it if there isin´t any update available lol

Explanation:

5 0

3 years ago

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How much extra water does a 21.5 ft, 175-lb concrete canoe displace compared to an ultra-lightweight 38-lb Kevlar canoe of the s

pantera1 [17]

Answer:

The volume of the extra water is $2.195 ft^{3}$

Solution:

As per the question:

Mass of the canoe, $m_{c} = 175 lb + w$

Height of the canoe, h = 21.5 ft

Mass of the kevlar canoe, $m_{Kc} = 38 lb + w$

Now, we know that, bouyant force equals the weight of the fluid displaced:

Now,

$V\rho g = mg$

$V = \frac{m}{\rho}$ (1)

where

V = volume

$\rho = 62.41 lb/ft^{3}$ = density

m = mass

Now, for the canoe,

Using eqn (1):

$V_{c} = \frac{m_{c} + w}{\rho}$

$V_{c} = \frac{175 + w}{62.41}$

Similarly, for Kevlar canoe:

$V_{Kc} = \frac{38 + w}{62.41}$

Now, for the excess volume:

V = $V_{c} - V_{Kc}$

V = $\frac{175 + w}{62.41} - \frac{38 + w}{62.41} = 2.195 ft^{3}$

8 0

3 years ago

The thrust F of a screw propeller is known to depend upon the diameter d,speed of advance \nu ,fluid density p, revolution per s

musickatia [10]

Answer:

<em>screw thrust = ML</em> $T^{-2}$ <em> </em>

Explanation:

thrust of a screw propeller is given by the equation = p $V^{2}$ $D^{2}$ x $\frac{ND}{V}$ Re

where,

D is diameter

V is the fluid velocity

p is the fluid density

N is the angular speed of the screw in revolution per second

Re is the Reynolds number which is equal to puD/μ

where p is the fluid density

u is the fluid velocity, and

μ is the fluid viscosity = kg/m.s = M $L^{-1}$ $T^{-1}$

<em>Reynolds number is dimensionless so it cancels out</em>

The dimensions of the variables are shown below in MLT

diameter is m = L

speed is in m/s = L $T^{-1}$

fluid density is in kg/ $m^{3}$ = M $L^{-3}$

N is in rad/s = L $L^{-1}$ $T^{-1}$ =

If we substitute these dimensions in their respective places in the equation, we get

thrust = M $L^{-3}$ $(LT^{-1}) ^{2}$ $L^{2}$ $\frac{T^{-1} L}{LT^{-1} }$

= M $L^{-3}$ $L^{2}$ $T^{-2}$

<em>screw thrust = ML</em> $T^{-2}$ <em> </em>

This is the dimension for a force which indicates that thrust is a type of force

6 0

3 years ago

Robots are made up of what

Nataly [62]

Answer:

Metal

Explanation:

Metal

8 0

3 years ago