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ololo11 [35]
4 years ago
6

A space probe is orbiting a planet on a circular orbit of radius R and a speed v. The acceleration of the probe is a. Suppose ro

ckets on the probe are fired causing the probe to move to another circular orbit of radius 0.5R and speed 2v. What is the magnitude of the probe’s acceleration in the new orbit?
Physics
1 answer:
Mamont248 [21]4 years ago
7 0

Answer:

acceleration in the new orbit is 8 time of acceleration of planet in old orbit

a_{new} = 8a.

Explanation:

given data:

radius of orbit = R

Speed pf planet = v

new radius = 0.5R

new speed = 2v

we know that acce;ration is given as

a = \frac{v^{2}}{R},

a_{new} =\frac{(2v)^{2}}{0.5R},

           = \frac{4v^{2}}{0.5R}

          = \frac{8 v^{2}}{R}

a_{new} = 8a.

acceleration in the new orbit is 8 time of acceleration of planet in old orbit

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dybincka [34]
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The time taken, and the distance travelled by the car before stop, will be 5.3 second and -53.3 m west.

<h3>What is the distance?</h3>

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Distance is a 1-dimensional phenomenon. its unit is a meter(m). The distance can be found by the product of velocity and time.

The given data in the problem will be

u is the initial velocity =20m/sec

t is the time =?

d is the distance =?

From the Newtons second law;

\rm  F \triangle t = \triangle P \\\\ \triangle t = \frac{\triangle P }{F} \\\\ \triangle t = \frac{m(v_f-v_i)}{F} \\\\ \ \triangle t = \frac{2240 (0-20))}{8410} \\\\ \triangle t = 5.3 \ sec \\\

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brainly.com/question/989117

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