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yKpoI14uk [10]
3 years ago
12

A cart traveling at 0.3 m/s collides with stationary object. After the collision, the cart rebounds in the opposite direction. T

he same cart again traveling at 0.3 m/s collides with a different stationary object. This time the cart is at rest after the collision. In which collision is the impulse on the cart greater?
A. The first collision.

B. Cannot be determined without knowing the rebound speed of the first collision.

C. The second collision.

D. Cannot be determined without knowing the mass of the cart.

E. The impulses are the same.
Physics
1 answer:
Nady [450]3 years ago
6 0
The first collision because a greater amount of momentum must be taken and used in order to push the cart back, giving it a greater mass and impulse
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a force is applied to a box of 10.0 kg for 4.0 s. the box goes from rest to 25 m/s in that time. What is the magnitude of that f
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Given:

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Now we know that

v=u+at

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nevsk [136]

Answer:

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This is a team building exercise to perform interference experiments, where the separation of the slits is d = 1 m = 1 10⁻³ m and the distance to the screen L = 1.5 m  

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   tan θ= y / L  

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we substitute  

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y = 1 500 10⁻⁹ 1.5 / 1 10⁻³  

y = 7.5 10⁻⁴ m  

yellow λ = 600 nm  

y = 1 600 10⁻⁹ 1.5 / 1.10⁻³  

y = 9 10⁻⁴ m  

lam λ = 700 nm  

y = 1 700 10⁻⁹ 1.5 / 1. 10⁻³  

y = 1.05 10⁻³ m  

violet, green, orange, red  

the distance increases with the wavelength increases

d) To find the wavelength we must measure the distance y from the center of the slit for various interference orders and using the equation we can find the wavelength of rationality

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