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3 years ago

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Ten students stand in a circle and are told to make a transverse wave. What best describes the motion of the students? Each stud

ent bumps the shoulder of his or her neighbor. At the exact time, all students take a step to the right. The students skip clockwise, going in a circular motion. One at a time, each student lifts his or her hands up and then down.

2 answers:

ELEN [110]3 years ago

6 0

Answer:

The correct option here is D.

<em>~Hope this helps! :)</em>

Bond [772]3 years ago

3 0

Lifting hands and the down by one student at a time best describe the presentation of the transverse wave by students. Option D is correct.

<h3>What is a Transverse wave?</h3>

The wave in which the oscillation of particles is is perpendicular to the direction of energy transfer.

The students can make a transverse wave by raising their hands up and then down, one student at a time.

The raised hand represents the oscillation of particles while the sequence of the raising hand represents the direction of energy transfer.

Therefore, lifting hands and the down by one student at a time best describe the presentation of the transverse wave by students.

Learn more about Transverse waves:

brainly.com/question/3813804

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Answer:

B

Explanation:

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Which of the following best describes the difference between type a and type b

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A small metal sphere weighs 0.34 N in air and has a volume of 13 cm3 . What is the acceleration of the sphere as it falls throug

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To solve this problem we will apply the concepts related to the balance of forces. Said balance will be given between buoyancy force and weight, both described as derived from Newton's second law, are given as

Buoyancy force

$F_B = V\rho g$

Here,

V = Volume

$\rho$ =Density of air

g = Acceleration due to gravity

Weight

$F_W = mg$

m = mass

g = Gravity

Our values are given as,

$\text{Weight of the sphere} = W = 0.34 N$

$\text{Volume} = V = 13 cm^3 = 13*10^{-6}m^3$

$\text{density of air} =\rho =1.29kg/m^3$

$\text{gravity}= g = 9.8 m/s^2$

Then,

$F = V\rho g$

Replacing,

$F = (13*10^{-6}m^3 )(1.29Kg/m^3)( 9.8 m/s^2) = 1.6434* 10^{-4} N$

Now net force is ,

$F_{net} = mg - F$

Mass of the sphere is

$m = \frac{W}{g} = \frac{0.34N}{9.8m/s^2} = 0.03469 kg$

Now acceleration of the sphere is

$a = \frac{F_{net}}{m}$

$a = \frac{( 0.34 N)- (1.6434* 10^{-4} N)}{0.03469 kg}$

$a = 9.822m/s^2$

Therefore the acceleration of the sphere as it falls through water is $9.822m/s^2$

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3 years ago

A well is being dug. A 4.5-kg bucket is filled with 28.0 kg of dirt and pulled vertically upward at a constant speed through a d

andreyandreev [35.5K]

The work done on the filled bucket in raising out of the hole is 2, 925 Joules

<h3>How to determine the work done</h3>

Using the formula:

Work done = force * distance

Note that force = mass * acceleration

F = mg + ma

F = 4. 5 * 10 + 28 * 10

F = 45 + 280

F = 325 Newton

Distance = 9m

Substitute into formula

Work done = 325 * 9

Work done = 2, 925 Joules

Therefore, the work done is 2, 925 Joules

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2 years ago

If six moles of hydrogen chloride (HCl) react with plenty of aluminum, how many moles of aluminum chloride (AlCl3) will the reac

AlexFokin [52]

Answer:

Two moles of aluminum chloride $(AlCl_3)$ are produced when six miles of hydrogen Chloride $(HCl)$ react with plenty of aluminum

Explanation:

6 Moles of $HCl$ will only react with 2 moles of $Al$ irrespective of the number of moles of each compound present. The reaction wiil take place in this ratio only. The products produced will be 2 moles of $AlCl_3$ and 3 moles of $H_2$ this ratio will also be constant.

So, six moles of hydrogen chloride $(HCl)$ will react with plenty of aluminum to produce many 2 moles of aluminum chloride $(AlCl_3)$ .

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3 years ago