Answer:
The Anatomy of a Lens
Refraction by Lenses
Image Formation Revisited
Converging Lenses - Ray Diagrams
Converging Lenses - Object-Image Relations
Diverging Lenses - Ray Diagrams
Diverging Lenses - Object-Image Relations
The Mathematics of Lenses
Ray diagrams can be used to determine the image location, size, orientation and type of image formed of objects when placed at a given location in front of a lens. The use of these diagrams was demonstrated earlier in Lesson 5 for both converging and diverging lenses. Ray diagrams provide useful information about object-image relationships, yet fail to provide the information in a quantitative form. While a ray diagram may help one determine the approximate location and size of the image, it will not provide numerical information about image distance and image size. To obtain this type of numerical information, it is necessary to use the Lens Equation and the Magnification Equation. The lens equation expresses the quantitative relationship between the object distance (do), the image distance (di), and the focal length (f)
Answer: 30 metres
Explanation:
Initial velocity of object = 120m/s
Time taken = 4.0s
Distance covered by object = ?
Recall that distance = (Change in velocity / Time taken)
Distance = (120m/s)/4.0s
= (120m/s) / 4.0s
= 30m
Thus, the object will be 30 metres high
Answer:
The correct option is;
Amplitude
Explanation:
When transmitting picture signals over the air by broadcasting stations, the signals are shifted into high frequency channels of Very High Frequency (VHF) or Ultra High Frequency (UHF) carrier currents and imposing the the television signal by changing the amplitude of the high frequency carrier current to match the transmitted television signal waveform shape
Answer:
roof bow upwards
Explanation:
The top of the roof of the small ranger vehicle will bow upwards. This is as a result of gas pressure on the soft ragtop roof.
- As air begins to fill the vehicle, pressure resonates in all direction proportionally.
- The pressure of the air will be greater than that which the roof can withstand and this forces the roof sky up.
- It is a common scene when we see roof of ragtop vehicles bowing upwards into the sky.
To solve letter a:
d1 = 85t1 = 16 km,
85t1 = 16,
t1 = 16 / 85 = 0.1882 h = 11.29 min.
d2 = 115t2 = 16 km,
115t2 = 16,
t2 = 16 / 115 = 0.139 h = 8.35 min.
t1 - t2 = 11.29 - 8.35 = 2.94 min.
Car #2 arrives 2.94 minutes sooner.
To solve letter b:
15 min = 1/4 h = 0.25 h.
d1 = d2,
115t = 85(t + 0.25),
115t = 85t + 21.25,
115t - 85t = 21.25,
30t = 21.25,
t = 21.25 / 30 = 0.71 h,
d = 115 * 0.71 = 81.65 km.
