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2 years ago

Help someone

Physics

1 answer:

NARA [144]2 years ago

5 0

Answer:

oh hey jacky HEHEHEHE

Explanation:

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For a study to accurately reflect a target population behavior, it must use __________ measures.

kari74 [83]

Answer: a. both reliable and valid

The parameters used to describe a particular trait or characteristic in a human behavior should be reliable and valid, in order to determine the response of the population with respect to a particular stimulus.

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2 years ago

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What is the acceleration of this object? The object's mass is 60 kg.

slamgirl [31]

We know, F = m*a
Here, F = 600-400 = 200 N downwards
m = 60 Kg

Substitute their values,
a = 200/60
a = 20/6
a = 10/3
a = 3.33 m/s² downwards

In short, Your Answer would be 3.33 m/s² downwards

Hope this helps!

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3 years ago

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What is the velocity of 360?

9966 [12]

Answer:

3/360 is 120. your velocity is 120

Explanation:

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3 years ago

A red laser with a wavelength of 670 nm and a blue laser with a wavelength of 450 nm emit laser beams with the same light power.

tatyana61 [14]

E=hf C=wavelength*F

E=hC/wavelength

E=(6.626*10^-34)*(3.00*10^8)/670*10^-9

E=(6.626*10^-34)*(3.00*10^8)/450*10^-9

6 0

3 years ago

A 0.272-kg volleyball approaches a player horizontally with a speed of 12.6 m/s. The player strikes the ball with her fist and c

Nady [450]

(a) +9.30 kg m/s

The impulse exerted on an object is equal to its change in momentum:

$I= \Delta p = m \Delta v = m (v-u)$

where

m is the mass of the object

$\Delta v$ is the change in velocity of the object, with

v = final velocity

u = initial velocity

For the volleyball in this problem:

m = 0.272 kg

u = -12.6 m/s

v = +21.6 m/s

So the impulse is

$I=(0.272 kg)(21.6 m/s - (-12.6 m/s)=+9.30 kg m/s$

(b) 155 N

The impulse can also be rewritten as

$I=F \Delta t$

where

F is the force exerted on the volleyball (which is equal and opposite to the force exerted by the volleyball on the fist of the player, according to Newton's third law)

$\Delta t$ is the duration of the collision

In this situation, we have

$\Delta t = 0.06 s$

So we can re-arrange the equation to find the magnitude of the average force:

$F=\frac{I}{\Delta t}=\frac{9.30 kg m/s}{0.06 s}=155 N$

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3 years ago