Answer:
T_ww = 43,23°C
Explanation:
To solve this question, we use energy balance and we state that the energy that enters the systems equals the energy that leaves the system plus losses. Mathematically, we will have that:
E_in=E_out+E_loss
The energy associated to a current of fluid can be defined as:
E=m*C_p*T_f
So, applying the energy balance to the system described:
m_CW*C_p*T_CW+m_HW*C_p*T_HW=m_WW*C_p*T_WW+E_loss
Replacing the values given on the statement, we have:
1.0 kg/s*4,18 kJ/(kg°C)*25°C+0.8 kg/s*4,18 kJ/(kg°C)*75°C=1.8 kg/s*4,18 kJ/(kg°C)*T_WW+30 kJ/s
Solving for the temperature Tww, we have:
(1.0 kg/s*4,18 kJ/(kg°C)*25°C+0.8 kg/s*4,18 kJ/(kg°C)*75°C-30 kJ/s)/(1.8 kg/s*4,18 kJ/(kg°C))=T_WW
T_WW=43,23 °C
Have a nice day! :D
I will go to school tomorrow .....is this present tense or past tense or future tense
K= 37°C+273.15
K= 310.15
Round to the nearest whole number
310K
Answer:
Explanation:
The frequency of a light is inversely proportional to its wavelength. It is given by:
The speed of the red light, v = 3.0 × 10⁸ m/s
The wavelength of the red light, λ = 690 nm = 690 ×10⁻⁹ m
Thus, the frequency of red light emitted by neon sign having wavelength 690 nm is
Answer: v = 11 m/s
Explanation:
If we ASSUME that the road is horizontal, not banked
The maximum friction force available is μmg
This will need to supply all of the required centripetal force
mv²/R = μmg
v = √(μgR) = √(0.28(9.8)(45)) = 11.1121...≈ 11 m/s
