How many grams are in 3.45 moles of CaCl2
1 answer:
Answer:
Explanation:
First we find the Molecular weight of CaCl2
looking at the periodic table the MW of Ca is 40.078 and Cl is 35.453 and the ratio of ca to cl is 1:2 so we multiply cl by 2 which is 35.453*2=70.906
we add them together: 40.078 + 70.906 = 110.984 g/mol
now:
* 3.45 mol
the mol cancels out and we left with 3.45 * 110.984 grams = 382.89 grams
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Answer:
530.835 g
Explanation:
First we convert 244 g of benzoic acid (C₇H₆O₂) to moles, using its molar mass:
- 244 g benzoic acid ÷ 122.12 g/mol = 2.00 moles benzoic acid
Theoretically,<em> one mol of ethyl benzene would produce one mol of benzoic acid</em>. But the experimental yield tells us that one mol of ethyl benzene will produce only 0.4 moles of benzoic acid.
With the above information in mind we convert 2.00 moles of benzoic acid into moles of ethyl benzene:
- 2.00 moles benzoic acid *
= 5.00 moles ethyl benzene
Finally we <u>convert moles of ethyl benzene </u>(C₈H₁₀)<u> into grams</u>, using its <em>molar mass</em>:
- 5.00 moles ethyl benzene * 106.167 g/mol = 530.835 g ethyl benzene