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Anvisha [2.4K]
4 years ago
6

How many grams are in 3.45 moles of CaCl2

Chemistry
1 answer:
Firdavs [7]4 years ago
6 0

Answer:

Explanation:

First we find the Molecular weight of CaCl2

looking at the periodic table the MW of Ca is 40.078 and Cl is 35.453 and the ratio of ca to cl is 1:2 so we multiply cl by 2 which is 35.453*2=70.906

we add them together: 40.078 + 70.906 = 110.984 g/mol

now:

\frac{110.984 grams}{mol} * 3.45 mol

the mol cancels out and we left with 3.45 * 110.984 grams = 382.89 grams

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nataly862011 [7]

Answer:

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Explanation:

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8 0
3 years ago
What is the ratio of lactic acid (Ka = 1.37x^10-4) to lactate in a solution with pH =4.29
hram777 [196]

Henderson–Hasselbalch equation is given as,

                                         pH  =  pKa  +  log [A⁻] / [HA]   -------- (1)

Solution:

Convert Ka into pKa,

                                         pKa  =  -log Ka

                                         pKa  =  -log 1.37 × 10⁻⁴

                                         pKa  =  3.863

Putting value of pKa and pH in eq.1,

                                         4.29  =  3.863 + log [lactate] / [lactic acid]

Or,

                   log [lactate] / [lactic acid]  =  4.29 - 3.863

                   log [lactate] / [lactic acid]  =  0.427

Taking Anti log,

                             [lactate] / [lactic acid]  =  2.673

Result:

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6 0
3 years ago
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I am not sure but this is what I think

This question uses the formula connecting mass, density and volume
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7.87g/ml = 92,500/ Volume
Volume= 92,500/7.87
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Now since we have to give the answer in liters we can just divide by 1000 and get
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creativ13 [48]

Answer:

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Explanation:

8 0
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Answer:

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