Answer;
= -2.18 × 10^-5 C
Explanation;
m = 1.49 × 10^-3 kg
Take downward direction as positive.
Fg = m g
E = 670 N/C
Fe = q E
Fe + Fg = 0
q E + m g = 0
q = -m g/E
= -1.49 × 10^-3 × 9.81/670
= -2.18 × 10^-5 C
= -2.18 × 10^-5 C
Answer:
I think d. is the answer I'm not conform
<h2><em>A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. You assume that the reference point is stationary, or not moving.</em></h2>
The kinematic equations of motion that apply here are<span>y(t)=votsin(θ)−12gt2</span>and<span>x(t)=votcos(θ)</span>Setting y(t)=0 yields <span>0=votsin(θ)−12gt2</span>. If we solve for t, we obtain, by factoring,<span>t=<span>2vsin(θ)g</span></span>Substitute this into our equation for x(t). This yields<span>x(t)=<span><span>2v2cos(θ)sin(θ)</span>g</span></span><span>This is equal to x=<span><span>v^2sin(2θ)</span>g</span></span>Hence the angles that have identical projectiles are have the same range via substitution in the last equation is C. <span> 60.23°, 29.77° </span>
Answer:
The value is 
Explanation:
From the question we are told that
The mass of the car is 
The period of the circular motion is 
The radius is 
Generally the frequency of the circular motion is
=> 
=>
