Answer:
See below
Explanation:
Vertical position = 45 + 20 sin (30) t - 4.9 t^2
when it hits ground this = 0
0 = -4.9t^2 + 20 sin (30 ) t + 45
0 = -4.9t^2 + 10 t +45 = 0 solve for t =4.22 sec
max height is at t= - b/2a = 10/9.8 =1.02
use this value of 't' in the equation to calculate max height = 50.1 m
it has 4.22 - 1.02 to free fall = 3.2 seconds free fall
v = at = 9.81 * 3.2 = 31.39 m/s VERTICAL
it will <u>also</u> still have horizontal velocity = 20 cos 30 = 17.32 m/s
total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s
Horizontal range = 20 cos 30 * t = 20 * cos 30 * 4.22 = 73.1 m
Answer:
length of a quarter wavelength antenna for transmitter elf waves are zero
Explanation:
Find the length of a quarter wavelength antenna for transmitter elf waves
Given information
frequency (ELF waves) → 77Hz
Speed of light → 3
m/s

where
→ wavelength of the antenna
f → frequency of the ELF waves
→ speed of light
so rewrite the equation in
from

Substitute
= 
Substitute 75Hz = f

m
since we get this value,but this size of antenna mount on submarine is not possible.
so
is zero
Answer:
a) 
b) 
Explanation:
Get the reactive powers for each of the loads:
Reactive power = Real Power * tanθ
For load 1
Active power, P₁ = 100 W
Power factor, 


For load 2
Active power, P₂ = 250 W
Power factor, 


For load 3
Active power, P₃ = 250 W
Power factor, 


Calculate the total reactive power, 

Calculate the total active power, 



V = 115 

b) Power factor of the composite load is 
