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Orlov [11]
3 years ago
12

When is Ampère’s Law valid? Evaluate all of the following statements, and explain your reasoning. a. When there is a high degree

of symmetry b. When there is no symmetry. c. When the current is constant. d. When the magnetic field is constant. e. In all of the above situations if the current is continuous.
Physics
1 answer:
Reil [10]3 years ago
8 0

Answer:

Check Explanation

Explanation:

Ampere's Law gives the expression for the magnetic field produced by current in a current carrying material.

Mathematically, it is explained that the product of permeability and current is equal to the sum of the dot product of the magnetic field in the direction of the length elements and the length elements.

μ₀I = ∫ B.dl (note that this integral is around the entire loop of current carrying material)

This law is valid for infinite current carrying wires because the magnetic field around such infinite current carrying wire is symmetrical.

The magnetic field around a finite length of wire is non-symmetrical and the current isn't continuous.

For Ampere's Law to work, the magnetic field around the wire must be symmetric, for straightforward computation and the current in the wire needs to be continuous, not cut short at the edges which makes the field around the wire non-symmetrical.

So, this condition is interlinked.

Hence, it is evident that only option A is absolutely correct.

Options C and D on their own aren't totally correct, but in conjunction with option E, they are correct.

Hope this Helps!!!

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Read 2 more answers
A car and a train move together along straight, parallel paths with the same constant cruising speed v0. At t=0 the car driver n
satela [25.4K]

Answer:

a) t1 = v0/a0

b) t2 = v0/a0

c) v0^2/a0

Explanation:

A)

How much time does it take for the car to come to a full stop? Express your answer in terms of v0 and a0

Vf = 0

Vf = v0 - a0*t

0 = v0 - a0*t

a0*t = v0

t1 = v0/a0

B)

How much time does it take for the car to accelerate from the full stop to its original cruising speed? Express your answer in terms of v0 and a0.

at this point

U = 0

v0 = u + a0*t

v0 = 0 + a0*t

v0 = a0*t

t2 = v0/a0

C)

The train does not stop at the stoplight. How far behind the train is the car when the car reaches its original speed v0 again? Express the separation distance in terms of v0 and a0 . Your answer should be positive.

t1 = t2 = t

Distance covered by the train = v0 (2t) = 2v0t

and we know t = v0/a0

so distanced covered = 2v0 (v0/a0) = (2v0^2)/a0

now distance covered by car before coming to full stop

Vf2 = v0^2- 2a0s1

2a0s1 = v0^2

s1 = v0^2 / 2a0

After the full stop;

V0^2 = 2a0s2

s2 = v0^2/2a0

Snet = 2v0^2 /2a0 = v0^2/a0

Now the separation between train and car

= (2v0^2)/a0 - v0^2/a0

= v0^2/a0

8 0
3 years ago
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