Answer:
The standard acceleration due to gravity (or standard acceleration of free fall), sometimes abbreviated as standard gravity, usually denoted by ɡ0 or ɡn, is the nominal gravitational acceleration of an object in a vacuum near the surface of the Earth. It is defined by standard as 9.80665 m/s2 (about 32.17405 ft/s2).
Explanation:
Addition of 2vector gives you 1large vector quantity
Answer:
A) Force
Explanation:
It is an example of force since force is a vector quantity so it has magnitude and direction. In this case the magnitude is equal to 5 [N] and the direction is upward.
The weight can not be, as it always acts downward.
Mass is not a force, its unit is given usually in kilogram [kg]
Answer:
0.1
Explanation:
mass, m = 5 kg
θ = 60°
Force, F = 10 N
velocity is constant , it means the net force is zero.
So, the component of force along the surface is equal to the friction force
FCosθ = friction force
10 x cos 60 = μ x m x g
where, μ is the coefficient of friction
5 = μ x 5 x 9.8
μ = 0.1
Thus, the coefficient of friction is 0.1
Answer:
The acceleration is:
Explanation:
To answer this, we need to recall Newton's Second Law of motion, that states that an object of mass m would accelerate (change its state of uniform motion) proportional to the force (F) that is applied , and exemplified by the following equation:
From here, and using the given values for mass (m = 3 kg) and force (F = 9 N), we can derive the value of the acceleration as shown below (notice that since all quantities are given in SI units, the resulting acceleration will also be in Si units ():