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yan [13]
3 years ago
9

1. Which of the following is NOT a cation?

Chemistry
1 answer:
Bezzdna [24]3 years ago
3 0
Hey Madoudou


The correct answer is option B (sulfate)


The reason is because "Sulfate" has a negative sign.

In order for it to be a cation, it must have positive sign such as "iron(lll)ion


I hope this helps~
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A because a primary source is defined as a first hand account of an event .
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Emission results in the release of energy without any apparent change in mass or nuclear charge.
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gamma ray

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A saturated solution of potassium chlorate is dissolved in 100g of water. If the saturated solution is cooled from 90 degrees Ce
dedylja [7]

Mass would crystallize out : 24 g

<h3>Further explanation </h3>

Solubility is the maximum amount of a substance that can dissolve in some solvents. Factors that affect solubility

  • 1. Temperature:
  • 2. Surface area:
  • 3. Solvent type:
  • 4. Stirring process:

We can use solubility graph to solve this.

solubility KClO₃ at 90°C=52 g

solubilty KCl₃ at 60°C= 28 g

Mass would crystallize out = 52 - 28 =24 g

4 0
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Fe(s) is already one atom and it is gas. Why do we call it a solid?
nadezda [96]
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3 years ago
171 g of sucrose ( MW of 342, melting point 186 oC, boiling point very high, and vapor pressure is negligible) is dissolved in o
Fantom [35]

The complete question is as follows: 171 g of sucrose ( MW of 342, melting point 186 oC, boiling point very high, and vapor pressure is negligible) is dissolved in one liter of water at 25 oC. At 25 oC the vapor pressure of water is 24 mmHg. Which value is closest to the vapor pressure (VP) of this solution at 25 oC?

a. 16mm Hg

b. 24mm Hg  

c. 20mm Hg  

d. 12mm Hg

Answer: The vapor pressure (VP) of this solution at 25^{o}C is closest to the value 24 mm Hg.

Explanation:

Given: Mass of sucrose = 171 g

Mass of water = 1 L = 1000 g

Vapor pressure of water = 24 mm Hg

As moles is the mass of substance divided by its molar mass. Hence, moles of water (molar mass = 18.02 g) is calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{1000 g}{18.02 g/mol}\\= 55.49 mol

Similarly, moles of sucrose (molar mass = 342 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\= \frac{171 g}{342 g/mol}\\= 0.5 mol

Total moles = 55.49 + 0.5 mol = 55.99 mol

Mole fraction of water is as follows.

Mole fraction = \frac{moles of water}{total moles}\\= \frac{55.49}{55.99}\\= 0.99

Formula used to calculate vapor pressure of the solution is as follows.

P_{i} = P^{o}_{i} \times \chi_{i}

where,

P_{i} = vapor pressure of component i over the solution

P^{o}_{i} = vapor pressure of pure component i

\chi_{i} = mole fraction of i

Substitute the values into above formula to calculate vapor pressure of water as follows.

P_{i} = P^{o}_{i} \times \chi_{i}\\= 24 mm Hg \times 0.99\\= 23.76 \\or 24 mm Hg\\

Thus, we can conclude that the vapor pressure (VP) of this solution at 25^{o}C is closest to the value 24 mm Hg.

4 0
3 years ago
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