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Cerrena [4.2K]
3 years ago
12

A private aviation helicopter's main rotor blades rotate at approximately

Physics
1 answer:
Arisa [49]3 years ago
4 0

Answer: 7.5 rev/s

Explanation:

We are given the angular velocity \omega a helicopter's main rotor blades:

\omega=450 rpm=450 \frac{rev}{min}

However, we are asked to express this \omega in the International Systrm (SI) units. In this sense, the SI unit for time is second (s):

\omega=450 \frac{rev}{min} \frac{1 min}{60 s}

\omega=7.5 \frac{rev}{s}

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3 years ago
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