<span>Answer: option (1) solubility of the solution increases.
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<span>Justification:
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<span>The solubility of substances in a given solvent is temperature dependent.
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<span>The most common behavior of the solubility of salts in water is that the solubiilty increases as the temperature increase.
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<span>To predict with certainty the solubility at different temperatures you need the product solubility constants (Kps), which is a constant of equlibrium of the dissolution of a ionic compound slightly soluble in water, or a chart (usually experimental chart) showing the solubilities at different temperatures.
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<span>KClO₃ is a highly soluble in water, so you do not work with Kps.
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<span>You need the solubility chart or just assume that it has the normal behavior of the most common salts. You might know from ordinary experience that you can dissolve more sodium chloride (table salt) in water when the water is hot. That is the same with KClO₃.
</span><span>The solubility chart of KlO₃ is almost a straight line (slightly curved upward), with positive slope (ascending from left to right) meaning that the higher the temperature the more the amount of salt that can be dissolved.</span>
<span>A covalent bond is a bond formed by atom sharing.
In water molecule, there are twice the number of hydrogen atoms than the oxygen atoms. Its structure is H-O-H. The electronegative difference between the H and O allows them to be polar because on side there is positive charge and on another side there is negative charge.</span>
Answer:
theory is diffrent from law
Explanation:
a Theory can never be proven to be true nd a law can usually be expressed
Since he’s watering it and it’s getting sun, i would say it’s because the soil isn’t rich enough and it doesn’t have the nutrients it needs for the plant to grow.
Answer:
1.6 L
Explanation:
Using Charle's law
Given ,
V₁ = 1.5 L
V₂ = ?
T₁ = 12 °C
T₂ = 32 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (12 + 273.15) K = 285.15 K
T₂ = (32 + 273.15) K = 305.15 K
Using above equation as:

New volume = 1.6 L