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3 years ago

What source of energy is responsible for the water cycle

Physics

1 answer:

Eduardwww [97]3 years ago

7 0

Water? The sun. I DUNNO I FEEL BAD :(

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A bus comes to rest by applying brakes in 10 second calculate the initial velocity of the bus and distance travelled during the

Rina8888 [55]

I dont know the answer to this question

7 0

3 years ago

At what point on the track does a roller coaster have the greates kinetic energy?

vredina [299]

At the bottom of the first and biggest drop. I hope I helped ^u^

3 0

3 years ago

Two rocks weighing 5 Newtons and 10 Newtons are dropped simultaneously from the same height onto a Coyote. After three seconds o

Ilia_Sergeevich [38]

<h2>Potential energy lost by 10 N rock will be greater</h2>

Explanation:

Two rocks of 5N and 10N falls from the same height . Thus they will loose the potential energy.

The potential energy lost = mass x acceleration due to gravity x height

The potential energy lost by first 5 N rock = 5 h

Because weight of rock m g = 5 N

Similarly , the potential energy lost by 10 N Rock = 10 h

here weight of rock m g = 10 N

Thus comparing these two , the potential energy lost by 10 N rock is greater than that of 5 N rock .

5 0

4 years ago

a mass of 1.00 kg of water at temperature T is poured from a height of 0.100 km into a vessel containing water of the same tempe

Mariana [72]

Answer:

1.34352 kg

Explanation:

$m_w$ = Mass of water falling = 1 kg

h = Height of fall = 0.1 km

$\Delta T$ = Change in temperature = 0.1

c = Specific heat of water = 4186 J/kg K

g = Acceleration due to gravity = 9.81 m/s²

$m_v$ = Mass of water in the vessel

Here the potential energy will balance the internal energy

$m_wgh=m_wc\Delta T+m_vc\Delta T\\\Rightarrow m_v=\dfrac{m_wgh-m_wc\Delta T}{c\Delta T}\\\Rightarrow m_v=\dfrac{m_wgh}{c\Delta T}-m_w\\\Rightarrow m_v=\dfrac{1\times 9.81\times 100}{4186\times 0.1}-1\\\Rightarrow m_v=1.34352\ kg$

Mass of the water in the vessel is 1.34352 kg

6 0

3 years ago

A man jogs at a velocity of 2.5 m/s west for 1,200 s. He then walks at a velocity 1.0 m/s east for 500 s and then stops to rest

olganol [36]

Speed of man towards West =2.5 m/s

Time to travel in the given direction = 1200 s

Total displacement towards west

$d_1 = v_1 t$

$d_1 = 2.5 \times 1200 = 3000 m$

Now speed of man towards East = 1 m/s

time to travel in east direction = 500 s

total displacement towards East

$d_2 = v_2 t$

$d_2 = 1 \times 500 = 500 m$

Now total displacement will be

$d = d_1 - d_2$

$d = 3000 - 500 = 2500 m$

so it is 2500 m towards west

5 0

3 years ago