When saturated air is cooled, it simply reaches its dew point. Dew point is simply the temperature at which dew begins to form.
Dew point of saturated air is already pre-determined by how much water vapor the air contains. A state of saturation exists when the air is holding the maximum amount of water vapor possible at the existing temperature and pressure. The higher the dew point, the higher the moisture content of the air. Cooling does not change the dew point of saturated air, rather its the level of saturation.
So if the air has more moisture, dew will form at a higher temperature and vice versa, but dew point is NEVER EVER GREATER than the air temperature.
Responder: A.) 24.5m / s B.) 30.625m C.) 89.375m
Explicación:
Dado lo siguiente:
Altura desde la cual se cae el cuerpo = 120 m
Tiempo (t) = 2.5s
A.) La velocidad que toma:
El cuerpo cayó desde una altura;
velocidad inicial (u) = 0
Para calcular v:
V = u + en
Donde a = aceleración debido a la gravedad = 9.8m / s
v = 0 + (9.8) (2.5)
v = 24.5 m / s
B) Cuánto ha disminuido.
Usando la ecuación de movimiento:
S = ut + 0.5at ^ 2
Donde S = distancia
S = 0 × 2.5 + 0.5 (9.8) (2.5 ^ 2)
S = 0 + 0.5 (9.8) (6.25)
S = 30.625 m
Esta es la distancia recorrida después de 2.5 segundos Altura o distancia ha disminuido en 30.625 m
C.) ¿CUÁNTO FALTA? Por lo tanto, 120m - 30.625m = 89.375m
Explanation:
y = ½ at²
Multiply both sides by 2:
2y = at²
Divide both sides by a:
t² = 2y/a
Take the square root of both sides:
t = √(2y/a)
Answer:
a) 
b) 
c) 
Explanation:
From the question we are told that:
Given Frequencies
a. 100 Hz,
b. 1 kHz,
c. 100 kHz.
Generally the equation for Waveform Period is mathematically given by

Therefore
a)
For



b)
For



c)
For



Answer and explanation: Just as the organs in an organ system work together to accomplish their task, so the different organ systems also cooperate to keep the body running. For example, the respiratory system and the circulatory system work closely together to deliver oxygen to cells and to get rid of the carbon dioxide the cells produce.