Answer:
a) Maximum speed = 25.28 m/s
b) Total time = 27.27 s
c) Total distance traveled = 402.43 m
Explanation:
a) Maximum speed is obtained after the end of acceleration
v = u + at
v = 13.5 + 1.9 x 6.2 = 25.28 m/s
Maximum speed = 25.28 m/s
b) We have maximum speed = 25.28 m/s, then it decelerates 1.2 m/s² until it stops.
v = u + at
0 = 25.28 - 1.2 t
t = 21.07 s
Total time = 6.2 + 21.07 = 27.27 s
c) Distance traveled for the first 6.2 s
s = ut + 0.5 at²
s = 13.5 x 6.2 + 0.5 x 1.9 x 6.2² = 120.22 m
Distance traveled for the second 21.07 s
s = ut + 0.5 at²
s = 25.28 x 21.07 - 0.5 x 1.2 x 21.07² = 282.21 m
Total distance traveled = 120.22 + 282.21 = 402.43 m
"<span>H-C=N:" is the one answer among the choices given in the question that shows the correct dot diagram. The correct option among all the options that are given in the question is the fourth option or option "D". The other choices can be neglected. I hope that this is the answer that has come to your help.</span>
Answer:
The new force between the charges becomes double of the initial force.
Explanation:
The force acting between charge particles is given by :
k is electrostatic constant
r is distance between charges
If one of the charges are doubled, then, q₁ = 2q₁
The new force becomes,
So, the new force between the charges becomes double of the initial force.
Answer:
The distance the car travels is 115500 m in S.I units
Explanation:
Distance d = vt where v = speed of the car and t = time taken to travel
Now v = 99 km/h. We now convert it to S.I units. So
v = 99 km/h = 99 × 1000 m/(1 × 3600 s)
v = 99000 m/3600 s
v = 27.5 m/s
The speed of the car is 27.5 m/s in S.I units
We now convert the time t = 70 minutes to seconds by multiplying it by 60.
So, t = 70 min = 70 × 60 s = 4200 s
The time taken to travel is 4200 s in S.I units
Now the distance, d = vt
d = 27.5 m/s × 4200 s
d = 115500 m
So, the distance the car travels is 115500 m in S.I units
