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3 years ago

Select inductive reasoning, deductive reasoning, or neither.

2 answers:

4 0

Based on the given situation above about the ants tasting a sample of a certain liquid, the kind of reasoning that is applicable to it would be inductive reasoning. Inductive reasoning is a kind of reasoning which is based on specific instances going to the conclusion.

Nataly_w [17]3 years ago

4 0

The correct answer of this question is A.Inductive reasoning.

As per this question the ant was allowed to have the liquid which was repeated for all ants and it was concluded that the liquid is an ant poison.

Inductive reasoning is based on specific observation which are used for making generalized statement or hypothesis which ultimately gives the conclusion. In the given question, specific example is stated which is giving the conclusion that liquid is an ant poison.Thus, this approach of reasoning is considered as inductive reasoning .

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Which shows the formula for converting from kelvins to degrees Celsius? °C = (9/5 × K) +32 °C = 5/9 × (K – 32) °C = K – 273 °C =

madam [21]

The freezing point of the water is 0 C , and it equals to 273 K

Then, To convert from Kelvins degrees to Celsius degrees we use the relation

$K = C + 273$

Also,

$C = K - 273$

5 0

3 years ago

Read 2 more answers

1. Two-point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude and direction of t

densk [106]

Answer:

F = 36 N

Explanation:

Given that,

Charge, q₁ = +8 μC

Charge, q₂ = -5 μC

The distance between the charges, r = 10 cm = 0.1 m

We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :

$F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\F=36\ N$

So, the magnitude of the electrostatic force is 36 N.

3 0

3 years ago

A car travelling 10m/s increases its speed to 20m/s over a time of 4s. What is the acceleration of the car? A car is traveling a

Alexxx [7]

Answer:

Explanation:

Acceleration is the change in velocity with respect to time.

Acceleration = change in velocity/Time

Acceleration = final velocity - initial velocity/Time

Given initial velocity = 10m/s

Final velocity = 20m/s

Time taken = 4s

Acceleration = 20-10/4

Acceleration = 10/4

Acceleration =2.5m/s²

For the second part of the question:

Given parameters

initial velocity = 15m/s

acceleration = -3m/s²

time = 4seconds

a = v-u/t

-3 = v-15/4

cross multiply

-12 = v-15

add 15 from both sides

-12+15 = v-15+15

3 = v

<em>Hence the final velocity of the car is 3m/s</em>

6 0

3 years ago

Ples help qustion in the image

ella [17]

I would say that an astronaut will fell the lightest in the moon because all of the low gravity.

Very appreciated if this answer helped you out .

6 0

3 years ago

A car accelerates uniformly from rest to 24.8 m/s in 7.88 s along a level stretch of road. Ignoring friction, determine the aver

nevsk [136]

Answer:

When he weight of the car is 8.55 x $10^{3}$ N then power = 314.012 KW

When he weight of the car is 1.10 x $10^{4}$ N then power = 43.76 KW

Explanation:

Given that

Initial velocity $V_{1}$ = 0

Final velocity $V_{2}$ = 24.8 $\frac{m}{s}$

Time = 7.88 sec

We know that power required to accelerate the car is given by

P = $\frac{change \ in \ kinetic \ energy}{time}$

Change in kinetic energy Δ K.E = $\frac{1}{2} m (V_{2}^{2} - V_{1}^{2} )$

Since Initial velocity $V_{1}$ = 0

⇒ Δ K.E = $\frac{1}{2} m V_{2} ^{2}$

⇒ Power P = $\frac{1}{2} \frac{m}{t} V_{2} ^{2}$

⇒ Power P = $\frac{1}{2} \frac{W}{g\ t} V_{2} ^{2}$ -------- (1)

(a). The weight of the car is 8.55 x $10^{3}$ N = 8550 N

Put all the values in above formula

So power P = $\frac{1}{2} \frac{8550}{(9.81)\ (7.88)} (24.8) ^{2}$

P = 314.012 KW

(b). The weight of the car is 1.10 x $10^{4}$ N = 11000 N

Put all the values in equation (1) we get

P = $\frac{1}{2} \frac{11000}{(9.81)\ (7.88)} (24.8) ^{2}$

P = 43.76 KW

5 0

3 years ago