Based on your question where a car leaves skid marks 85m long on the highway nad getting to stop. The deceleration of the car is 3m/s^2 to estimate the speed of the car just before braking first is to analyze the problem then apply the necessary formulas. the possible answer is 510m/s
Answer:
The magnitude of the magnetic torque on the coil is 1.98 A.m²
Explanation:
Magnitude of magnetic torque in a flat circular coil is given as;
τ = NIASinθ
where;
N is the number of turns of the coil
I is the current in the coil
A is the area of the coil
θ is the angle of inclination of the coil and magnetic field
Given'
Number of turns, N = 200
Current, I = 7.0 A
Angle of inclination, θ = 30°
Diameter, d = 6 cm = 0.06 m
A = πd²/4 = π(0.06)²/4 = 0.002828 m²
τ = NIASinθ
τ = 200 x 7 x 0.002828 x Sin30
τ = 1.98 A.m²
Therefore, the magnitude of the magnetic torque on the coil is 1.98 A.m²
Answer:
Tangential speed = R * w where w is the angular speed
For a wheel v = .114 m * 6.53 / sec = .744 m/s
Note that this is the tangential speed - If the wheel were moving at speed V then as viewed from the ground you have
top V + v
bottom V - v
That is the wheel also has speed due to the speed of the axle (axis of rotation)
