Ask question

Ask question

All categories

aleksandrvk [35]

3 years ago

14

How many grams of copper can be produced from 15.6 grams of silver based on the following reaction? 2Ag(s) + CuSO4(aq)—> Cu(s

) +Ag2 SO4(s)

1 answer:

aev [14]3 years ago

5 0

ijmmmmmmmmmmmmmmmmmmmmmmmmi

You might be interested in

25. Which answer best describes the continental rise? area of land that drops toward deep ocean basins 75 mile shallow flat area

Hatshy [7]

Answer:

Thick deposits of sediments carried off of the shelf

Explanation:

The continental rise is a thick deposit of sediments that accumulate between the continental slope and the abyssal plain

A is wrong. The area of land that drops toward the deep ocean basins is the continental slope.

B is wrong. The 75-mile shallow flat area just off coastlines is the continental shelf.

D is wrong. The surf area along coastlines is the surf zone .

8 0

3 years ago

If you added 45,000 calories to water that was at 25 degrees C, and the ending temperature was 35 degrees C, how much water did

user100 [1]

<u>Answer:</u>

<em>4.5 L water we have in litres (L).</em>

<em><u></u></em>

<u>Explanation:</u>

$Q=m\times c \times \Delta T$

where

$\Delta T$ = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for water 1.0 cal/(g℃))

m is the mass of water

Plugging in the values

$\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times\left(35^{\circ} \mathrm{C}-25^{\circ} \mathrm{C}\right)$\\\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}$\\\\$m=\frac{45000 \mathrm{cal}}{1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}}$\\\\$m=4500 \mathrm{g}$\\\\Density of water $=\frac{\text { mass }}{\text { volume }}$$

So,

Volume of water = mass/density

$\\\\=\frac{4500 \mathrm{g}}{\frac{1.09}{\mathrm{mL}}}=4500 \mathrm{mL}$$$

=4.5 L (Answer)

6 0

3 years ago

An ideal gas in a sealed container has an initial volume of 2.80 L. At constant pressure, it is cooled to 18.00 °C, where its

Aleks04 [339]

Answer:

$T_1=-91.18\°C$

Explanation:

Hello there!

In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

$\frac{T_1}{V_1}= \frac{T_2}{V_2}$

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

$T_1= \frac{T_2V_1}{V_2}\\\\T_1= \frac{(18.00+273.15)K(1.75L)}{(2.80L)}\\\\T_1=182K-273.15\\\\T_1=-91.18\°C$

Best regards!

6 0

3 years ago

What structural features help us identify a compound as an alkane, a cycloalkane, an alkene, an alkyne, a saturated hydrocarbon

elena55 [62]

1. Cycloalkane
2. Alkene
3. Saturated Hydrocarbon
4. Aromatic Hydrocarbon
5. Alkane
6. Alkyne

5 0

3 years ago

Conduct research to examine the following factors regarding the storage of nuclear waste.

Airida [17]

The costs, risks, and benefits to building a nuclear waste storage facility somewhere else

7 0

3 years ago