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Valentin [98]
3 years ago
8

Water acts as a solvent. a. True b. False

Chemistry
1 answer:
Talja [164]3 years ago
7 0
True. Water acts as a solvent as the solute dissolves into water. 
You might be interested in
Why are metals alloyed?
Lady_Fox [76]
Because alloys have qualities that are preferable to pure metals, almost all metals are utilised as alloys—that is, mixes of several elements. Alloying is done for a variety of purposes, the most common of which are to increase strength, corrosion resistance, or cost savings.
5 0
2 years ago
Please help me with chemistry!
Helga [31]

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

Explanation:

Reacting bromide (Br₂) with sodium iodine (NaI) will produce sodium bromide (NaBr) and iodine (I₂).

To balance the equation the number of atoms of each element entering the  reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

where:

l - liquid

s - solid

This is a single replacement reaction because an element in a compound is replaced by another element. Generally a single replacement reaction is represented as: A + BC → AC + B

Learn more about:

types of chemical reactions

brainly.com/question/10105284

balancing chemical equations

brainly.com/question/13908054

#learnwithBrainly

5 0
3 years ago
During the chemical reaction given below 21.71 grams of each reagent were allowed to react. Determine how many grams of the exce
swat32

Answer: 16.32 g of O_2 as excess reagent are left.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} SO_2=\frac{21.71g}{64g/mol}=0.34mol

\text{Moles of} O_2=\frac{21.71g}{32g/mol}=0.68mol

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)  

According to stoichiometry :

2 moles of SO_2 require = 1 mole of O_2

Thus 0.34 moles of SO_2 will require=\frac{1}{2}\times 0.34=0.17moles  of O_2

Thus SO_2 is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

Moles of O_2 left = (0.68-0.17) mol = 0.51 mol

Mass of O_2=moles\times {\text {Molar mass}}=0.51moles\times 32g/mol=16.32g

Thus 16.32 g of O_2 as excess reagent are left.

3 0
3 years ago
Balanced nuclear equation forces the alpha decay Po-210
Serjik [45]

Answer:

_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} \, + \, _{2}^{4}\text{He}

Explanation:

Your unbalanced nuclear equation is:

_{84}^{210}\text{Po} \longrightarrow \, _{x}^{y}\text{Z} + \, _{2}^{4}\text{He}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

 84 = x + 2, so x =  84 - 2 =   82

210 = y + 4, so y = 210 - 4 = 206

Element 82 is lead, so the nuclear equation becomes

_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} \, + \, _{2}^{4}\text{He}

8 0
3 years ago
What describes the solvent in any solution
Lady_Fox [76]
Solvent is more than a solute. Like salt water. Water is the solvent and salt will be the solute
5 0
3 years ago
Read 2 more answers
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