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ZanzabumX [31]
3 years ago
10

*̶*̶*̶G̶I̶V̶E̶A̶W̶A̶Y̶*̶*̶*̶ ̶F̶r̶e̶e̶ ̶9̶9 ̶p̶t̶s̶ ̶f̶o̶r̶ ̶t̶h̶i̶s̶ ̶q̶u̶e̶s̶t̶i̶o̶n

Physics
2 answers:
marusya05 [52]3 years ago
7 0
Earthquakes happen<span> when rock below the Earth's surface moves abruptly. </span>Usually, the rock is moving along large cracks in Earth's crust called faults. Most earthquakes happen<span> at or near the </span>boundaries<span> between Earth's </span>tectonic plates <span>because that's where there is </span>usually<span> a large concentration of faults</span>
malfutka [58]3 years ago
3 0
Because of the release of built up stress between the rocks constitute each plate.
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A stone with a weight of 5.30 N is launched vertically from ground level with an initial speed of 23.0 m/s, and the air drag on
frozen [14]

Answer:

a) h=25.7\ m

b) v'=21.8733\ m.s^{-1}

Explanation:

Given:

  • weight of the stone, w=5.3\ N
  • initial velocity of vertical projection, u=23\ m.s^{-1}
  • air drag acting opposite to the motion of the stone, D=0.266\ N

The mass of the stone:

m=\frac{w}{g}

m=\frac{5.3}{9.8}

m=0.5408\ kg

Now the acceleration of the stone opposite of the motion:

D=m.d

where:

d = deceleration

0.266=0.5408\times d

d=0.4918\ m.s^{-2}

<u>In course of going up the net acceleration on the stone will be:</u>

g'=g+d

g'=9.8+0.4918

g'=10.2918\ m.s^{-2}

a)

Now using the equation of motion:

v^2=u^2-2 g'.h

where:

v= final velocity when the stone reaches at the top of the projectile = 0

h = height attained by the stone before starting to fall down

0^2=23^2-2\times 10.2918\times h

h=25.7\ m

b)

during the course of descend from the top height of the projectile:

initial velocity, v=0\ m.s^{-1}

The acceleration will be:

g"=g-d

g"=9.8-0.4918

g"=9.3082\ m.s^{-2}

here the gravity still acts downwards but the drag acceleration acts in the direction opposite to the motion of the stone, now the stone is falling down hence the drag  acts upwards.

Using equation of  motion:

v'^2=v^2+2g".h (+ve acceleration because it acts in the direction of motion)

v'^2=0^2+2\times 9.3082\times 25.7

v'=21.8733\ m.s^{-1}

8 0
3 years ago
A device that does work with one movement and changes the size or direction of a force is a(n)
tresset_1 [31]
A device that does work with one movement and changes the size or direction of a force is a simple machine.
7 0
3 years ago
Read 2 more answers
What is a hypothesis
notsponge [240]
A hypothesis can be described as an intelligent guess 
7 0
3 years ago
Consider a situation of simple harmonic motion in which the distance between the endpoints is 2.39 m and exactly 8 cycles are co
aivan3 [116]

Answer:

1.195 m

2.8375 s

2.21433 rad/s

Explanation:

d = Distance = 2.39 m

N = Number of cycles = 8

t = Time to complete 8 cycles = 22.7 s

Radius would be equal to the distance divided by 2

r=\frac{d}{2}\\\Rightarrow r=\frac{2.39}{2}\\\Rightarrow r=1.195\ m

The radius is 1.195 m

Time period would be given by

T=\frac{t}{N}\\\Rightarrow T=\frac{22.7}{8}\\\Rightarrow T=2.8375\ s

Time period of the motion is 2.8375 s

Angular speed is given by

\omega=\frac{2\pi}{T}\\\Rightarrow \omega=\frac{2\pi}{2.8375}\\\Rightarrow \omega=2.21433\ rad/s

The angular speed of the motion is 2.21433 rad/s

4 0
3 years ago
A rescue plane flying horizontally at 72.6 m / s spots a survivor in the ocean 182 m directly below and releases an emergency ki
Mila [183]

Answer:

547 m

Explanation:

From law of motion

s = ut + ½at²

Where "t" is Time taken to reach Earth

s= distance= 182 m

a= vertical acceleration = 5.82 m / s 2

U= initial velocity in vertical position = 0

182= ½ × 5.82t²

t²=( 2× 182)/ 5.82

= 364/5.82

= 62.54

t= √62.54

t= 7.908s

horizontal distance travelled = speed x time

Horizontal speed= 72.6 m / s

horizontal distance travelled =72.6× 7.908

= 547 m

Hence, the survivor will it hit the waves at 547 m away

3 0
3 years ago
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