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olasank [31]
3 years ago
6

What is the Moleular geometry of Xe0F4

Chemistry
1 answer:
Rudiy273 years ago
3 0

Answer:

Central atom: Xe

Total VSEP: 7

1 x double bond − 1 pair

Revised Total: 6

Geometry: Square pyramidal (based on octahedral)Explanation:

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Inference

Explanation:

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What type of element is fluorine
Serga [27]

Answer:

It is a halogen element

Explanation:

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4 0
3 years ago
When 16 g of methane (CH4) and 32 g of oxygen (O2) reacted to produce carbon dioxide and water, 11 g of carbon dioxide was produ
Aliun [14]

Answer:

Percent yield = 50%

Explanation:

Given data:

Mass of CH₄ = 16 g

Mass of O₂ = 32 g

Mass of CO₂ = 11 g

Percent yield of CO₂ = ?

Solution:

Chemical equation:

CH₄ + 2O₂    →  CO₂ + 2H₂O

Number of moles of CH₄:

Number of moles = mass/ molar mass

Number of moles = 16 g /16 g/mol

Number of moles = 1 mol

Number of moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 32 g /32 g/mol

Number of moles = 1 mol

Now we will compare the moles of CO₂ with both reactant.

                             O₂             :            CO₂

                              2              :               1

                              1               :          1/2×1= 0.5 mol

                          CH₄              :            CO₂

                             1               :               1

Number of moles of CO₂ produced by oxygen are less so it will limiting reactant.

Theoretical yield:

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 0.5 mol × 44 g/mol

Mass = 22 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 11 g/ 22 g × 100

Percent yield = 50%

3 0
3 years ago
A sample of neon gas occupies 105 L at 27°C under a pressure of
Viefleur [7K]

Answer: Volume occupied by given neon sample at standard condition is 123.84 L.

Explanation:

Given: V_{1} = 105 L,    T_{1} = 27^{o}C = (27 + 273) K = 300 K,     P_{1} = 985 torr

At standard conditions,

T_{2} = 273 K,     P_{2} = 760 K,        V_{2} = ?

Formula used to calculate the volume is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{985 torr \times 105 L}{300 K} = \frac{760 torr \times V_{2}}{273 K}\\V_{2} = \frac{94116.75}{760} L\\= 123.84 L

Thus, we can conclude that volume occupied by given neon sample at standard condition is 123.84 L.

8 0
3 years ago
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