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2 years ago

15

To win a prize at the county fair, you're trying to knock down a heavy bowling pin by hitting it with a thrown object. Should yo

u choose to throw a rubber ball or a beanbag of equal size and weight?

1 answer:

Setler [38]2 years ago

8 0

Answer:

Being an elastic object, rubber ball will be an ideal choice as it will bounce off the bowling pit and will experience a large change in momentum in comparison with the beanbag which will either slow down or come to a halt upon hitting a bowling pit. That is why rubber ball will experience a greater impulse and the bowling pin will experience the negative impulse of the rubber ball.

For Rubber Ball

Upon elastic collision it will reverses the direction and move with velocity equal or less then original

change in momentum = P

$P = m(v_{f} -v_{i})\\v_{f}=-v_{i} \\ P = -2mv_{i}$

For Beanbag

value of impulse will large if velocity is zero.

$v_{f}=0\\ P = -mv_{i}$

Explanation:

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Two loudspeakers are placed on a wall 2 m apart. A listener stands directly in front of one of the speakers, 81.7 m from the wal

OverLord2011 [107]

Answer:

The phase difference is $\Delta \phi = 1.9995 rad$

Explanation:

From the question we are told that

The distance between the loudspeakers is $d = 2m$

The distance of the listener from the wall $D = 81.7 \ m$

The frequency of the loudspeakers is $f = 4450Hz$

The velocity of sound is $v_s = 343 m/s$

The path difference of the sound wave that is getting to the listener is mathematically represented as

$\Delta z =\sqrt{d^2 + D^2} -D$

Substituting values

$\Delta z =\sqrt{2^2 + 81.7^2 } -81.7$

$\Delta z =0.0245m$

The phase difference is mathematically represented as

$\Delta \phi$ = $\frac{2 \pi}{\lambda } * \Delta z$

Where $\lambda$ is the wavelength which is mathematically represented as

$\lambda = \frac{v_s }{f}$

substituting value

$\lambda = \frac{343 }{4450}$

$\lambda = 0.0770 m$

Substituting value into the equation for phase difference

$\Delta \phi$ = $\frac{2 * 3.142 * 0.0245}{0.0770}$

$\Delta \phi = 1.9995 rad$

8 0

3 years ago

The current world-record motorcycle jump is 77.0 m, set by Jason Renie. Assume that he left the take-off ramp at 13.0° to the ho

kotegsom [21]

Answer:

The take-off speed is 41.48 $\frac{m}{s}$

Explanation:

Given :

Range $R = 77$ m

Projectile angle $\alpha =$ 13°

From the formula of range,

$R = \frac{v_{o} ^{2} }{g} \sin 2\alpha$

Find the velocity from above equation,

$v_{o} = \sqrt{\frac{gR}{\sin 2 \alpha } }$

$v_{o} = \sqrt{\frac{9.8 \times 77}{\sin 26} }$ ( ∵ $g = 9.8$ $\frac{m}{s^{2} }$ )

$v_{o} = 41.48$ $\frac{m}{s}$

Therefore, the take-off speed is 41.48 $\frac{m}{s}$

7 0

3 years ago

a boy takes 15min to reach his school on bicycle.if the bicycle have speed of 2m/s the what is the distance between the house an

Rom4ik [11]

<h2>Answer:</h2>

The distance will be 1800 m

<h2>Explanation</h2>

As in question

Time = 15 min

Time = 15 x 60 sec = 900 sec

Speed = 2 m/s

We know that

$Distance = Speed x Time$

$Distance = 2 x 900$

$Distance = 1800 m$

So, the answer is 1800 m

4 0

3 years ago

If an astronaut goes on a space walk outside the Space Station, she will quickly float away from the station unless she has a te

Strike441 [17]

Answer:

d. This statement is false. She and the Space Station share the same orbit and will stay together unless they are pushed apart.

Explanation:

In astronomy, orbit is simply a path of an object around another object in a space. That is, orbit is a path of a body that revolves around a gravitating center of mass. Examples of an orbit is are satellite around a planet, orbit around a center of galaxy, planet around the sun, and among others.

On the other hand, space station refers to a spacecraft that can support a group of human for long time in the orbit. Another names for space stations are orbital space station and orbital station.

Therefore, an astronaut goes on a space walk outside the Space Station shares the same orbit with the space station and they will stay together unless they are pushed apart.

4 0

3 years ago

A system absorbed 44 joules of heat from its surroundings. After doing work, the increase in the internal energy of the system i

Lunna [17]

Idk sorry maybe try @amyletbe

6 0

3 years ago

Read 2 more answers