Here,
Load distance (Ld) = 30 cm
Effort distance (Ed) = 60 cm
Load (L) = 200N
Effort (E) = ?
Now, By using formula,
or, E * Ed = L * Ld
or, E * 60 = 200 * 30
or, E = 6000/60
◆ E = 100N
This is a Right answer...
I hope you understand...
Answer: 0.72 grams
Explanation: Mass can be extracted from the formula of density. D=M/V where D is density and V is volume. Therefore:
18 g/cm^3 = M(25 cm^3) --> Divide by 18g/cm^3 by 25 cm^3 to isolate mass. --> <u>0.72 =M </u> --> Now, to find out which unit you need to use for mass, just look at the density. You can see it is in g/cm^3, and cm^3 was already used for the volume. Thus, gram units are left, so that will be the unit needed, making the final answer 0.72 grams. Hope this helps :)
Answer:
Magnitude of the force between the charges is F = 1.92×10^20N
Explanation:
Given the magnitude of force according to coulombs law
F =K[(q1*q2)/r2]
Where q1 and q2 are the charges
r is the distance between the charges
K is the coulombs constant
Substituting the given values, we have;
F = 8.98×10^9 × 1.5×10^6 × 3.2×10^4/1.5²
F = 43.1×10^19/2.25
F = 19.16×10^19N
F = 1.92×10^20N
Answer:

Explanation:
We need to apply conservation of momentum and energy to solve this problem.
<u>Conservation of momentum</u>

(1)
- m(c) is the mass of stick clay
- m(w) is the mass of the wooden block
- v(ic) is the initial velocity of clay
- V is the final velocity of the system clay plus wood.
<u>Conservation of total energy</u>
The change in kinetic energy is equal to the change in internal energy, in our case it would be the energy loss due to the friction force. Let's recall the definition of work, it is the dot product between force and displacement, Therefore:



We can find V from this equation:

Now, let's put V into the equation (1) and find v(ic)

I hope it helps you!
<u />
The correct answer is '44'.
In fact, the atom of an element has an equal number of protons and electrons: therefore, if element X has 44 protons, it should have 44 electrons as well.
For curiosity: the chemical element with 44 protons and 33 electrons is Ruthenium.