A museum curator moves artifacts into place on various different display surfaces. If the curator moves a 145 kg aluminum sculpt
2 answers:
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Answer:
q₃=5.3nC
Explanation:
First, we have to calculate the force exerted by the charges q₁ and q₂. To do this, we use the Coulomb's Law:
Since we know the net force, we can use this to calculate q₃. As q₁ is at the right side of q₃ and q₁ and q₃ have opposite signs, the force F₁₃ points to the right. In a similar way, as q₂ is at the left side of q₃, and q₂ and q₃ have equal signs, the force F₂₃ points to the right. That means that the resultant net force is the sum of these two forces:
In words, the value of q₃ must be 5.3nC.
Answer:
a = 2 [m/s^2]
Explanation:
To solve this problem we must use the expressions of kinematics, we must bear in mind that when a body is at rest its velocity is zero.
where:
Vf = final velocity = 0
Vi = initial velocity = 60 [m/s]
a = desacceleration [m/s^2]
t = time = 30 [s]
Note: the negative sign of the above equation means that the car is slowing down, i.e. its speed decreases.
0 = 60 - (a*30)
a = 2 [m/s^2]
Answer:
796.2 m.
Explanation:
A sketch of the given question forms a right angled triangle with two given sides and a non included angle. Applying the appropriate trigonometric function, we have;
Tan θ =
Let the horizontal distance required be represented by x, so that;
Tan =
0.7536 =
⇒ x =
= 796.1783
x = 796.2 m
Thus, the horizontal distance of the point of impact is 796.2 m.