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4 years ago

7

Tell me the weirdest and stupidest story EVER! If it's sooooo incredibly stupid and funny i will give you a thanks, 5 stars, 15

points, and Brainliest!!!

1 answer:

trasher [3.6K]4 years ago

6 0

Answer:

Once upon a time, there was this strong man, no sorry i meant weak pathetic boi. He had a very smoll pp. And one day he thouht he could beat up his friend. He went to him a got flicked and went flying and he died later that day.

Explanation:

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An ethylene glycol solution contains 21.4 g of ethylene glycol (C2H6O2) in 97.6 mL of water. (Assume a density of 1.00 g/mL for

8090 [49]

Answer: The freezing point and boiling point of the solution are $-6.6^0C$ and $101.8^0C$ respectively.

Explanation:

Depression in freezing point:

$T_f^0-T^f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_f$ = freezing point of solution = ?

$T^o_f$ = freezing point of water = $0^0C$

$k_f$ = freezing point constant of water = $1.86^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(0-T_f)^0C=1\times (1.86^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_f=-6.6^0C$

Therefore,the freezing point of the solution is $-6.6^0C$

Elevation in boiling point :

$T_b-T^b^0=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of water = $100^0C$

$k_b$ = boiling point constant of water = $0.52^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(T_b-100)^0C=1\times (0.52^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_b=101.8^0C$

Thus the boiling point of the solution is $101.8^0C$

4 0

4 years ago

This is usually used for school work but, I'm using it for something different. You see, I like this dude that I met over playst

shusha [124]

Answer:

The best way to admit you like him would be to act normal. Don't be someone your not and just admit to him that you like him. Yolu could do it while ya'll are talking but don't just suddenly spring it on him. If he is a true friend, your friendship will remain even if he doesn't like you back.

Explanation:

8 0

3 years ago

Noble gas notation write the electron configuration for the manganese atom

8_murik_8 [283]

<span> the electron configuration for the manganese atom [Ne]3s</span>²

6 0

3 years ago

What is the energy transferred by a force to a moving object?

eimsori [14]

Answer: The energy transferred is known as kinetic energy, and it depends on the mass and speed achieved.

3 0

3 years ago

2Mg + O2à MgO For this unbalanced chemical equation, what is the coefficient for oxygen when the equation is balanced? A. 1 B. 2

Vikki [24]

Answer:

The answer to your question is the letter A. 1

Explanation:

Unbalanced chemical reaction

Mg + O₂ ⇒ MgO

Reactants Elements Products

1 Magnesium 1

2 Oxygen 1

Balanced chemical reaction

2Mg + O₂ ⇒ 2MgO

Reactants Elements Products

2 Magnesium 2

2 Oxygen 2

Conclusion

The coefficients of the balanced equation are 2, 1, 2

7 0

3 years ago

Read 2 more answers