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Brilliant_brown [7]
3 years ago
14

Glycolysis produces NADH . However, NADH cannot cross the inner mitochondrial membrane to be used in the electron transport chai

n (respiratory chain). The malate–aspartate shuttle in some animal cells transfers electrons from cytosolic NADH to the matrix. How is oxaloacetate modified to a form that can be transported out of the matrix? transamination isomerization dehydrogenation uncoupling Which compound is transported across the inner membrane in exchange for malate? NADH α‑ketoglutarate aspartate glutamate oxaloacetate
Chemistry
1 answer:
matrenka [14]3 years ago
7 0

Answer: 1.) oxaloacetate can be modified to a form that can be transported out of the matrix through TRANSAMINATION.

2.) The compound that is transported across the inner membrane in exchange for malate is α‑KETOGLUTARATE.

Explanation:

The malate- aspartate shuttle is a system that allows electrons to move across membrane between the cytosol and mitochondrial matrix. The electrons generated during glycolysis such as NADH cannot cross the inner mitochondrial membrane to be used in the electron transport chain (respiratory chain). Therefore through reduction- oxidation reactions, the malate- aspartate shuttle regenerates NADH inside the mitochondrial matrix which can be used to pass electrons to the electron transport chain so that ATP can be synthesized.

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Which product forms from a reaction between beryllium (Be) and arsenic (As)?
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Answer:

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3 years ago
The vapor pressure of water at 25.0°c is 23.8 torr. determine the mass of glucose (molar mass = 180 g/mol) needed to add to 500.
svp [43]
Q: A
according to this formula, we can get the mole fraction of water (n):
P(solu) = n Pv(water)
when we have Pv(solu) = 22.8 and Pv(water) = 23.8 so by substitution:
22.8 = n * 23.8
n= 0.958
- we need to get the moles of glucose:
moles of water = 500 g(mass weight) / 18 (molar weight)= 27.7 mol
n = moles of water / ( moles of water + moles of glucose)
0.958   = 27.7 / ( 27.7+ moles of glucose)
0.958 moles of glucose + 26.5 = 27.7
0.968 moles of glucose = 1.2
moles of glucose = 1.253 mol
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Q: B
here we also need to get n (mole fraction of water )by using this formula:
Pv(solu) = n Pv(water)
when we have Pv(solu)=132 & Pv(water)=150 so, by substition:
132= n * 150
n = 0.88
so, mole fraction of solution = 1 - 0.88 = 0.12
and we can get after that the moles of water = (mass weight / molar mass)
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- total moles in solution = moles of water / moles fraction of water 
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∴ moles of the solution = total moles in solu - moles of water 
                                       = 5.34 - 4.7 = 0.64 moles solute
∴ the molar mass of the solute = mass weight of solute / no.of moles of solute
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Q: C

moles of urea (NH2)2 CO = mass weight / molar mass
                                           = 4.49 g / 60 g /mol
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by substitution in Pv formula we will be able to get the vapour pressure of the solu :
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Given:
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