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Brilliant_brown [7]
2 years ago
14

Glycolysis produces NADH . However, NADH cannot cross the inner mitochondrial membrane to be used in the electron transport chai

n (respiratory chain). The malate–aspartate shuttle in some animal cells transfers electrons from cytosolic NADH to the matrix. How is oxaloacetate modified to a form that can be transported out of the matrix? transamination isomerization dehydrogenation uncoupling Which compound is transported across the inner membrane in exchange for malate? NADH α‑ketoglutarate aspartate glutamate oxaloacetate
Chemistry
1 answer:
matrenka [14]2 years ago
7 0

Answer: 1.) oxaloacetate can be modified to a form that can be transported out of the matrix through TRANSAMINATION.

2.) The compound that is transported across the inner membrane in exchange for malate is α‑KETOGLUTARATE.

Explanation:

The malate- aspartate shuttle is a system that allows electrons to move across membrane between the cytosol and mitochondrial matrix. The electrons generated during glycolysis such as NADH cannot cross the inner mitochondrial membrane to be used in the electron transport chain (respiratory chain). Therefore through reduction- oxidation reactions, the malate- aspartate shuttle regenerates NADH inside the mitochondrial matrix which can be used to pass electrons to the electron transport chain so that ATP can be synthesized.

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A 0.4272 g sample of an element contains 2.241 x 10 ^21 atoms . what is the symbol of the element?
grin007 [14]

Answer:

Likely \rm In (indium.)

Explanation:

Number of atoms: N = 2.241 \times 10^{21}.

Dividing, N, the number of atoms by the Avogadro constant, N_A \approx 6.023 \times 10^{23} \; \rm mol^{-1}, would give the number of moles of atoms in this sample:

\begin{aligned} n &= \frac{N}{N_{A}} \\ &\approx \frac{2.241 \times 10^{21}}{6.023 \times 10^{23}\; \rm mol^{-1}} \approx 3.72 \times 10^{-3}\; \rm mol \end{aligned}.

The mass of that many atom is m = 0.4272\; \rm g. Estimate the average mass of one mole of atoms in this sample:

\begin{aligned}M &= \frac{m}{n} \\ &\approx \frac{0.4272\; \rm g}{3.72 \times 10^{-3}\; \rm mol} \approx 114.82\; \rm g \cdot mol^{-1}\end{aligned}.

The average mass of one mole of atoms of an element (114.82\; \rm g \cdot mol^{-1} in this example) is numerically equal to the average atomic mass of that element. Refer to a modern periodic table and look for the element with average atomic mass 114.82. Indium, \rm In, is the closest match.

5 0
3 years ago
Electromagnetic Waves can propagate (move through);
wariber [46]

Answer:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

Explanation:

5 0
2 years ago
At 600. K how many moles of gas are in a 1.00 L cylinder at atmospheric pressure?
Anton [14]

Answer:

0.02moles

Explanation:

To answer this question, the general gas law equation is used. The General gas law is:

Pv = nRT

Where; P = standard atmospheric pressure (1 atm)

V = volume (L)

n = number of moles

R = Gas law constant

T = Temperature

For this question; volume = 1.00L, atmospheric pressure (P) = 1 atm, R = 0.0821 L-atm / mol K, T = 600K, n = ?

Therefore; Pv = nRT

n = PV/RT

n = 1 × 1/ 0.0821 × 600

n = 1/49.26

n = 0.0203moles

Hence, there are 0.02 moles of gas.

8 0
3 years ago
1. Determine the molecular formula of an oxide of iron in which the mass of iron and oxygen are 69.9% and 30% respectively given
Scorpion4ik [409]

1a. The empirical formula of the compound is Fe₂O₃

1b. The molecular formula of the compound is Fe₂O₃

2a. The molecular formula of the anhydrous salt is MgSO₄

2b. The formula of the crystalline salt is MgSO₄.7H₂O

3i. The number of mole of carbon atoms in the compound is 6 moles

3ii. The number of mole of hydrogen atoms in the compound is 18 moles

3iii. The number of molecules in 3 moles of ethane is 1.806×10²⁴ molecules

<h3>1a. How to determine the empirical formula</h3>
  • Fe = 69.9%
  • O = 30%
  • Empirical formula =?

Divide by their molar mass

Fe = 69.9 / 56 = 1.248

O = 30 / 16 = 1.875

Divide by the smallest

Fe = 1.248 / 1.248 = 1

O = 1.875 / 1.248 = 3/2

Multiply by 2 to express in whole number

Fe = 1 × 2 = 2

O = 3/2 × 2 = 3

Thus, the empirical formula of the compound is Fe₂O₃

<h3>1b. How to determine the molecular formula</h3>
  • Empirical formula = Fe₂O₃
  • Molar mass of compound = 159.89 g/mol
  • Molecular formula = ?

Molecular formula = empirical × n = molar mass

[Fe₂O₃]n = 159.89

[(56×2) + (16×3)]n = 159.89

160n = 159.89

n = 159.89 / 160

n = 1

Molecular formula = [Fe₂O₃]n

Molecular formula = [Fe₂O₃] × 1

Molecular formula = Fe₂O₃

<h3>2a. How to determine the molecual formula of the anhydrous salt</h3>

We'll begin by calculating the empirical formula

  • Mg = 20.0%
  • S = 26.66%
  • O = 53.33%
  • Empirical formula =?

Divide by their molar mass

Mg = 20.0 / 24 = 0.83

S = 26.66 / 32 = 0.83

O = 53.33 / 16 = 3.33

Divide by the smallest

Mg = 0.83 / 0.83 = 1

S = 0.83 / 0.83 = 1

O = 3.33 / 0.83 = 4

Thus, the empirical formula of the anhydrous salt is MgSO₄

The molecular formula of the anhydrous salt can be obtained as follow:

  • Empirical formula = MgSO₄
  • Molar mass of compound = 120 g/mol
  • Molecular formula = ?

Molecular formula = empirical × n = molar mass

[MgSO₄]n = 120

[24 + 32 + (16×4)]n = 159.89

120n = 120

n = 120 / 120

n = 1

Molecular formula = [MgSO₄]n

Molecular formula = [MgSO₄] × 1

Molecular formula = MgSO₄

<h3>2b. How to determine the formula of the crystalline salt</h3>
  • Water (H₂O) = 51.2%
  • Anhydrous salt (MgSO₄) = 100 - 51.2 = 48.8%
  • Formula of crystalline salt =?

Divide by their molar mass

MgSO₄ = 48.8 / 120 = 0.4

H₂O = 51.2 / 18 = 2.8

Divide by the smallest

MgSO₄ = 0.4 / 0.4 = 1

H₂O = 2.8 / 0.4 = 7

Thus, the formula of the crystalline salt is MgSO₄.7H₂O

<h3>3i. How to determine the mole of carbon atoms in 3 moles of C₂H₆</h3>

1 mole of C₂H₆ contains 2 moles of carbon atoms.

Therefore,

3 moles of C₂H₆ will contain = 3 × 2 = 6 moles of carbon atoms

<h3>3ii. How to determine the mole of hydrogen atoms in 3 moles of C₂H₆</h3>

1 mole of C₂H₆ contains 6 moles of hydrogen atoms.

Therefore,

3 moles of C₂H₆ will contain = 3 × 6 = 18 moles of hydrogen atoms

<h3>3iii. How to determine the number of molecules</h3>

From Avogadro's hypothesis,

1 mole of ethane = 6.02×10²³ molecules

Therefore,

3 moles of ethane = 3 × 6.02×10²³ molecules

3 moles of ethane = 1.806×10²⁴ molecules

Learn more about empirical formula:

brainly.com/question/24297883

Learn more about Avogadro's number:

brainly.com/question/26141731

#SPJ1

Complete question

2. A crystalline salt when heated becomes anhydrous and loses 51.2% of its weight the anhydrous salt analysis gave the percent composition as magnesium is equal to 20.0% and sulphur is equal to 26.66% and oxygen is equal to 53.33%. Ccalculate the molecular formula of the anhydrous and the crystalline salt. The molecular weight of the anhydrous salt is 120

4 0
2 years ago
A current of electricity flowing through a wire will create an)
Lera25 [3.4K]

Answer:

electrical field.

hope it helps.

5 0
2 years ago
Read 2 more answers
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