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Levart [38]
4 years ago
14

On a planet far, far away, an astronaut picks up a rock. The rock has a mass of 4.80 kg , and on this particular planet its weig

ht is 41.5 N . You may want to review (Pages 121 - 129) . Part A If the astronaut exerts an upward force of 48.1 N on the rock, what is its acceleration
Physics
1 answer:
Oksanka [162]4 years ago
3 0

Answer:

   a = 1,375 m / s²

Explanation:

For this exercise we use Newton's second law where the force applied by the astronaut is F = 48.1, the body weight is W = 41.5 N and the body mass is m = 4.80 kg

              F - W = m a

              a = (F -W) / m

let's calculate

              a = (48.1 - 41.5) / 4.80

              a = 1,375 m / s²

this acceleration is directed upwards

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You are correct. Mountains are part of the lithosphere.
8 0
3 years ago
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You work at a garden store for the summer, and you lift a 14 kg bag of fertilizer with a force of 227 N.
nika2105 [10]

Answer:

(a) Acceleration of the bag will be a=16.214m/sec^2  

(B) Weight of the bag will be 137.2 N

Explanation:

We have given mass of the bag m = 14 kg

Force with which bag is lifted = 227 N

(A) According to newtons law we force is equal to F = ma , here m is mass and a is acceleration

So 227=14\times a

a=16.214m/sec^2

(b) Acceleration due to gravity g=9.8m/sec^2

We know that weight is given by W = mg , here m is mass and g is acceleration due to gravity

So weight W=mg=14\times 9.8=137.2N

So weight of the bag will be 137.2 N

8 0
3 years ago
If your car is moving at 100 km/hr, how many kilometers will your car travel in 15 minutes?
steposvetlana [31]
It will be 25 if the car moves at that speed for 15 minutes
8 0
1 year ago
A long solenoid that has 1 200 turns uniformly distributed over a length of 0.420 m produces a magnetic field of magnitude 1.00
Fantom [35]

Answer:

<h2>The current required  winding is  2.65*10^-^2 mA</h2>

Explanation:

We can use the expression B=μ₀*n*I-------1 for the magnetic field that enters a coil  and

n= N/L (number of turns per unit length)

Given data

The number of turns n= 1200 turns

length L= 0.42 m

magnetic field B= 1*10^-4 T

μ₀= 4\pi*10^-^7 T.m/A

Applying the equation  B=μ₀*n*I

I= B/μ₀*n

I= B*L/μ₀*n

I= \frac{1*10^-^4*0.42}{4\pi*10^-^7*1.2*10^3 }

I= 2.65*10^-^2 mA

8 0
3 years ago
In a fluorescent tube of diameter 4.8 cm , 2.7 × 1018 electrons (with a charge of −e) and 2.4 × 1018 positive ions (with a charg
Lesechka [4]

Answer: 0.817A

Explanation:

Assuming , that one coulomb per second of negative charge alone flow through a conductor and no positive charges flow. I.e Q=It

It means a current of one A flow in the opposite direction.

This is similar to one coulomb per second of positive charge flowing through and there is no negative charge,

In addition, the one coulomb per second of positive charge flows. This is flowing in the current direction of the previous one. Then, the total current is 2 A. Since 2 coulomb of positive charges flow through one due to real positive charge and another due to the negative charge flowing in opposite direction.The charges cannot cancel each other, because even before the current flow the conductor was neutral.

According to this, the current in the given problem is

[2.7 + 2.4] x 10 ^ 18 * 1.602 x 10^ [-19] C/s

= 0.817 A

7 0
4 years ago
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