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Mnenie [13.5K]
3 years ago
6

Explain how to count the number of elements in a compound

Chemistry
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

Using the formula cards again, add the coefficient of 2 in front of the formula and have them recalculate the number of each element and the total number of atoms in each element.

Explanation:

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_ S8 +_02 +_ SO3
BigorU [14]
My educated guess should be the 3rd one
3 0
2 years ago
What is atoms in your own words
san4es73 [151]

Atom is the smallest indivisible particle of matter.

6 0
3 years ago
Can someone please help I need help?!?!
anzhelika [568]

Answer:

a: 6 moles

b: 6.75 moles

c: 5 grams

Explanation:

a: mole ratio 2:3

b: mole ratio 2:3

c: mole ratio 2:2

7 0
3 years ago
What volume would a 0. 250 mole sample of h2 gas occupy if it had a which a a pressure of 1. 70 atm and a temperature of 35 C?
frosja888 [35]

The volume of  0. 250 mole sample of H_{2} gas occupy if it had a pressure of 1. 70 atm and a temperature of 35 °C is  3.71 L.

Calculation,

According to ideal gas equation which is known as ideal gas law,

PV =n RT

  • P is the pressure of the hydrogen gas  = 1.7 atm
  • Vis the volume of the hydrogen gas = ?
  • n is the number of the hydrogen gas = 0.25 mole
  • R is the universal gas constant = 0.082 atm L/mole K
  • T is the temperature of the sample = 35°C = 35 + 273 = 308 K

By putting all the values of the given data like pressure temperature universal gas constant and number of moles in equation (i) we get ,

1.7 atm×V = 0.25 mole ×0.082 × 208 K

V = 0.25 mole ×0.082atm L /mole K × 308 K /1.7 atm

V = 3.71 L

So, volume of the sample of the hydrogen gas occupy is  3.71 L.

learn more about ideal gas equation

brainly.com/question/4147359

#SPJ4

4 0
1 year ago
I am having some trouble figuring out how to approach the following problem: A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is ti
Tanya [424]
<span>We look at the end of the day:

n(HNO3) added = 0.500*17.0/1000 = 0.00850 mol
n(NH3) = 0.200*75.0/1000 - 0.00850 = 0.00650 mol
[NH3] left = 0.00650*1000/(17.0+75.0) = 0.070652
M [OH-] = Kb * [NH3] = 0.070652*1.8*10^(-5) = 1.27174 x 10^(-6)
pOH = -log[OH-] ≈ 5.8956 pH = 14 - pOH ≈ 8.10</span>
4 0
2 years ago
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