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DanielleElmas [232]
4 years ago
15

if a bullet fired beneath the water, straight up, breaks through the surface at a speed of 25m/s, how high will the bullet be af

ter 2.8 seconds? what is the bullet's velocity at this time? (accelaration of 9.8m/s)
Physics
1 answer:
Doss [256]4 years ago
8 0

Answer:

32 m and -2.4 m/s

Explanation:

Given:

v₀ = 25 m/s

t = 2.8 s

a = -9.8 m/s²

Find: Δy, v

Δy = v₀ t + ½ at²

Δy = (25 m/s) (2.8 s) + ½ (-9.8 m/s²) (2.8 s)²

Δy = 31.6 m

v = at + v₀

v = (-9.8 m/s²) (2.8 s) + 25 m/s

v = -2.44 m/s

Rounded to two significant figures, the bullet reaches a height of 32 m and a velocity of -2.4 m/s.

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A student finds an unlabeled liquid container in his lab. He notices that the container has two liquids. Since the two liquids h
raketka [301]

Answer:

\rho = 1848.03 kg m^{-3}

Explanation:

given data:

density of water \rho = 1 gm/cm^3 = 1000 kg/m^3

height  of water  = 20 cm  =0.2 m

Pressure  p = 1.01300*10^5 Pa

pressure at bottom

P =  P_{fluid} + P_{h_2 o}

P   = P_{fluid}  + \rho g h

P_{fluid}  = P - \rho g h

                 = 1.01300*10^5 - 1000*0.2*9.8

                 = 99340 Pa

p_{fluid}  = P_{atm} + \rho g h_{fluid}                       h_[fluid} = 0.307m

99340 = 104900 + \rho *9.8*0.307

\rho = 1848.03 kg m^{-3}

5 0
4 years ago
In one or two sentences, explain design modifications which were implemented after the tacoma bridge disaster
iren [92.7K]

The modifications that are implemented after Tacoma bridge disaster are added trusses and openings below road decks to decrease oscillations.

<h3>Why Tacoma Bridge disaster occurred?</h3>

While marching, the natural frequency of the vibrations of marching soldiers matched up with the resonant frequency of the bridge. This resulted in the collapsing of the bridge in seconds.

Because of the disaster of the Tacoma Narrows Bridge, the bridge was strengthened by adding trusses as well as openings below road decks so as to decrease vibrations caused by running vehicles on the bridge.

Thus, the modifications that are implemented after Tacoma bridge disaster are added trusses and openings below road decks to decrease oscillations

Learn more about Tacoma Bridge disaster.

brainly.com/question/17924109

#SPJ1

4 0
3 years ago
What types of ions will sodium and chlorine each form? Explain
vaieri [72.5K]

Answer:

The sodium forms cations and chlorine forms anions.

Explanation:

  1. During the formation of the bonding, the sodium atom loses one electron and forms a positively charged ion called cation.
  2. The chlorine atom receives one electron and forms a negatively charged ion called anion.
  3. The electro-negativity of the atom determines the bonding nature of the atoms.
  4. In case of sodium and chlorine, it forms the ionic bonding where there is a transfer of an electron from one atom to the other.
  5. Hence the charge is given by Na⁺ and Cl⁻
8 0
4 years ago
PLEASE HELP ME
Ipatiy [6.2K]

Answer:

the time period is 22.63 years

Explanation:

The computation of the number of years taken is as follows:

According to the Keplers law

T^2 \propto R^3

Here T denotes the time period

And, R denotes the average distance among the sun and planet

Now let us assume for earth

R_1 & T_1 be 1 year

So, for Planet

R_2 = 8R_1 , T_2 = ?

Now applied Keplers law

(\frac{T_2}{T_1})^2 \propto (\frac{R_2}{R_1})^3\\\\(T_2)^2 = (\frac{8R_1}{R_1})^3 \times 1^2\\\\(T_2)^2 = 512\\\\T_2 = 22.674

So, the time period is 22.63 years

8 0
4 years ago
A 2.2 kg ball is attached to a ceiling by a string. The distance from the ceiling to the center of the ball is 1.06 m, and the h
Veronika [31]

Answer:

U=-22.85J

Explanation:

The potential energy associated with a body (m) located at a given height (h) above a reference point is defined as:

U=mgh

At the reference point the potential energy is zero. In this case the body is below the reference point (the ceiling), therefore, the value of h is negative:

U=2.2kg*9.8\frac{m}{s^2}*(-1.06m)\\U=-22.85J

3 0
3 years ago
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