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Aleonysh [2.5K]
3 years ago
5

The qualitative equivalent of external validity is:

Physics
1 answer:
Setler79 [48]3 years ago
7 0
C transformability i think
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Por favor ayuda que ejercicio debo hacer para enflacar en una semana xd
Serggg [28]

Answer:

Un excelente ejercicio para perder barriga rápidamente es correr, ya que el cuerpo gasta una mayor cantidad de calorías en un corto período de tiempo, en tan sólo 30 minutos corriendo se queman unas 300 calorías.

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Explanation:

dame coronita por favor

8 0
3 years ago
Grace rides her bike at a constant speed of 6 miles per hour. How far can she travel in 2 1/2 hours?
nydimaria [60]

Answer:

15~miles

Explanation:

2\frac{1}{2}*6=\frac{2*2+1}{2}*6=\frac{5}{2}*6=\frac{30}{2}=15~miles

7 0
3 years ago
In which direction does gravitational force act
Sunny_sXe [5.5K]
Gravitational force pushes down on us to keep us on the ground. So it pushes in a downward direction.
4 0
3 years ago
Two balls with equal masses, m, and equal speed, v, engage in a head on elastic collision. what is the final velocity of each ba
Allushta [10]
The collision is elastic. This means that both momentum and kinetic energy are conserved after the collision.

- Let's start with conservation of momentum. The initial momentum of the total system is the sum of the momenta of the two balls, but we should put a negative sign in front of the velocity of the second ball, because it travels in the opposite direction of ball 1. So ball 1 has mass m and speed v, while ball 2 has mass m and speed -v:
p_i = p_1-p_2 = mv-mv =0
So, the final momentum must be zero as well:
p_f = 0
Calling v1 and v2 the velocities of the two balls after the collision, the final momentum can be written as
p_f = mv_1 + mv_2 = 0
From which
v_1 = -v_2

- So now let's apply conservation of kinetic energy. The kinetic energy of each ball is \frac{1}{2} mv^2. Therefore, the total kinetic energy before the collision is
K_i = \frac{1}{2} mv^2 +  \frac{1}{2} mv^2 = mv^2
the kinetic energy after the collision must be conserved, and therefore must be equal to this value:
K_f = K_i = mv^2 (1)
But the final kinetic energy, Kf, is also
K_f =  \frac{1}{2} mv_1^2 +  \frac{1}{2}mv_2^2
Substituting v_1 = -v_2 as we found in the conservation of momentum, this becomes
K_f = mv_2 ^2
we also said that Kf must be equal to the initial kinetic energy (1), therefore we can write 
mv_2^2 = mv^2

Therefore, the two final speeds of the balls are
v_2 = v
v_1 = -v_2 = -v

This means that after the collision, the two balls have same velocity v, but they go in the opposite direction with respect to their original direction.

8 0
3 years ago
Why can acceleration include only a change in direction?
Fynjy0 [20]

First we shall look at some terms:

Velocity - frequency of change of an objects position.

Acceleration - frequency of change of an objects velocity


Since velocity covers both change in direction and speed, we can asume that the answer is B, not because it's the only one we worked with, but because the others don't make any sense:

A - this is not correct, because a chnage in direction can be done withough a change in speed.

C - The scientific definition of acceleration does include speed, and this is not a reasonable answer.

D - Velocity can change, unlike said in the sentence.


Hope it helped,


BioTeacher101

6 0
4 years ago
Read 2 more answers
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