Heya!
For this problem, use the formula:
s = Vo * t + (at^2) / 2
Since the initial velocity is zero, the formula simplifies like this:
s = (at^2) / 2
Clear a:
2s = at^2
(2s) / t^2 = a
a = (2s) / t^2
Data:
s = Distance = 518 m
t = Time = 7,48 s
a = Aceleration = ¿?
Replace according formula:
a = (2*518 m) / (7,48 s)^2
Resolving:
a = 1036 m / 55,95 s^2
a = 23,34 m/s^2
The aceleration must be <u>23,34 meters per second squared</u>
The average velocity is 40 km/hr Southeast.
Normal force, weight, Kinetic friction, and air resistance are a few I think of the top of my head.
I hope this helps
<h2>
Right answer: 64 units</h2><h2>
</h2>
According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:
Where:
is the module of the force exerted between both bodies
is the universal gravitation constant.
and 
are the masses of both bodies.
is the distance between both bodies
In this case we have a gravitation force 
, given by the formula written at the beginning. Let’s rename the distance as 
:
(1)
And we are asked to find the gravitation force 
with a given distance of 
:
(2)
The gravity constant is the same for both equations, and we are assuming both masses are constants, as well. So, let’s isolate 
in both equations:
From (1):
(3)
From (2):
(4)
If (3)=(4):
(5)
Now we have to find :
(6)
If 
:
>>>>This is the new force of attraction
Blue and yellow make green
